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Scrat [10]
3 years ago
9

Evaluate a + 4 a+4a, plus, 4 when a = 7 a=7a, equals, 7.

Mathematics
1 answer:
Scilla [17]3 years ago
4 0

<em>When evaluating a=7 then we get that the expression is 11</em>

<h2>Explanation:</h2>

As I understand the expression is the following:

a+4

Let's call, that expression as E

So we are asked to find the value of the expression when a=7. In other words, we need to substitute a=7, so:

E(7)=(7)+4 \\ \\ E(7)=11

So <em>when evaluating a=7 then we get that the expression is 11</em>

<h2>Learn more:</h2>

Distributive property: brainly.com/question/10794694

#LarnWithBrainly

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The ordered pairs
Paul [167]

Answer:

Step-by-step explanation:

Slope of the line through (0,3) and (2,5) = (5-3)/(2-0) = 1.

Equation of line: y = x+3

When x=3, y=6

(3,n) = (3,6)

5 0
2 years ago
F(x) = 2x2 – x + 9<br> Find f (4)
Alex

Answer:

45

Step-by-step explanation:

F(-4). F(x) = 2x^2 - x + 9

3 0
3 years ago
Find the center, vertices, and foci for the ellipse 25x^2+64y^2=1600
Ronch [10]

Answer:

Step-by-step explanation:

Answer:

Data

Equation               25x² + 64y² = 1600

Process

1.- Divide all the equation by 1600

                            25x²/1600 + 64y²/ 1600 = 1600/1600

-Simplify

                             x²/64 + y²/ 25 = 1

2.- Equation of a horizontal ellipse

                            

3.- Find a, b and c

   a² = 64             a = 8

   b² = 25             b = 5

-Calculate c with the Pythagorean theorem

                  a² = b² + c²

-Solve for c

                  c² = a² - b²

-Substitution

                  c² = 8² - 5²

-Simplification

                 c² = 64 - 25

                 c² = 39

-Result

                 c = √13

4.- Find the center

         C = (0, 0)

5.- Find the vertices

         V1 = (-8, 0)     V2 = (8, 0)

6.- Find the foci

         F1 = (-√13, 0)   F2 = (√13, 0)

4 0
3 years ago
Read 2 more answers
All four B points are equidistant from points A and C. Are they all midpoints of AC? Justify your answer.
Rina8888 [55]

Answer:

No

Step-by-step explanation:

For a point to be the midpoint of a line segment, it must bisect it into two equal segments and be on the line segment (hence, colinear with the endpoints). All four B points are equidistant from points A and C, but aren’t colinear with A and C. Therefore, they aren’t all midpoints of line segment AC.

I hope this helps! :)

5 0
2 years ago
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dezoksy [38]

Answer:

11

Step-by-step explanation:

2.2x 5 = 11

6 0
3 years ago
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