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3 years ago

5

How do I use the arc length to find the circumference ?

1 answer:

Mashutka [201]3 years ago

8 0

<span>arc length = circumference • [central angle (degrees) ÷ 360]

Solving this equation for circumference:
</span>
<span>circumference = arc length / (central angle / 360)

</span><span>circumference = 12 / (85/360)

</span>circumference = 12 / <span><span>0.2361111111 </span>
</span>
<span>circumference = </span> <span> <span> <span> 50.8235294118 </span> </span> </span>

Source:
http://www.1728.org/radians.htm

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Romashka-Z-Leto [24]

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Now we want to calculate te density of the material, as you know:

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3 years ago

What is the hypothesis of a triangle with a base of 11cm and height of 9cm

natima [27]

<u>Answer:</u>

<h2>14.21 cm</h2>

<u>Explanation:</u>

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the hypotenuse = √(121+81)

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2 years ago

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frosja888 [35]

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3 years ago

Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the

sp2606 [1]

Given:

The given quadratic polynomial is :

$x^2-x-12$

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

$x^2-x-12$

Equate the polynomial with 0 to find the zeroes.

$x^2-x-12=0$

Splitting the middle term, we get

$x^2-4x+3x-12=0$

$x(x-4)+3(x-4)=0$

$(x+3)(x-4)=0$

$x=-3,4$

The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

$x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}$

$x^2-(3+(-4))x+(3)(-4)$

$x^2-(-1)x+(-12)$

$x^2+x-12$

Therefore, the required polynomial is $x^2+x-12$ .

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3 years ago

5<br> 8<br> y<br> Find the exact value of y.<br> y =

inn [45]

Answer:

$y=2\sqrt{10}$

Step-by-step explanation:

By applying geometric mean theorem in the given right angle,

$\frac{AD}{DB}=\frac{DB}{CD}$

By substituting values in the given ratio,

$\frac{5}{y}= \frac{y}{8}$

$y^2=8\times 5$

$y^2=40$

$y=2\sqrt{10}$

Exact value of y is $2\sqrt{10}$ .

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3 years ago