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USPshnik [31]
3 years ago
15

Bridgette opened a store credit card to purchase a business suit for $463. She put the entire purchase on the credit card. Her A

PR is 14.99% and the minimum payment is 5%. Assuming she makes only minimum payments, what is the remaining balance on her card after 3 months? Can someone help me .
Mathematics
1 answer:
irinina [24]3 years ago
5 0
Begin by computing the <span>monthly interest rate like this:
</span>\frac{14.99}{12}=1.25
<span>Each month, we have to substract from $463 the monthly rate and the payment of 5%, which result in the following formula:
</span>463(1-(0.05+0.0125))^3=463\times0,9375^3\\=381.5
<span>
So, after three months, it ill remains $381.5 in </span><span>Bridgette account. </span>
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What is the range of the function y= -|x|
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Hope this helps!! Let me know if you have ANY questions.
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The Pacific halibut fishery has been modeled by the differential equation dy dt = ky 1 − y K where y(t) is the biomass (the tota
Dafna1 [17]

Answer:

a. The biomass weighs 2.30 * 10^7 kg after a year

b. It'll take 2.56 years to get to 4*10^7kg

Step-by-step explanation:

a.

k = 0.78,K = 6E7 kg

Given

dy/dt = ky(1- y/K)

Make ky dt the subject of formula

ky dt = dy/(1-y/K) --- make k dt the subject of formula

k dt = dy/(y(1-y/K))

k dt = K dy / y(K-y)

k dt = ((1/y) + (1/(K-y)))dy ---- integrate both sides

kt + c = ln(y/(K-y))

Ce^(kt) = y/(K-y)

Substitute the values of k and K

Ce^(0.78t) = y/(6*10^7 - y) ----- (1)

Given that y(0) = 2 * 10^7kg

(1) becomes

Ce^(0.78*0) = (2 * 10^7)/(6*10^7 - 2*10^7)

Ce° = (2*10^7)/(4*10^7

C = 2/7

Substitute 2/7 for C in (1)

2/7e^0.78t = y/(6*10^7 - y) ---(2)

We're to find the biomass a year later

So, t = 1

2/7e^0.78 = y/(6*10^7 - y)

0.62 = y/(6*10^7 - y)

y = 0.62(6*10^7 - y)

y = 0.62*6*10^7 - 0.62y

y + 0.62y = 0.62*6*10^7

1.62y = 0.62*6*10^7

1.62y = 3.72 * 10^7

y = 2.30 * 10^7kg.

Hence, the biomass weighs 2.30 * 10^7 kg after a year

b.

Here, we're to calculate the time it'll take the biomass to get to 4*10^7 kg

Substitute 4*10^7 for y in (2)

2/7e^0.78t = 4*10^7/(6*10^7 - 4*10^7)

2/7e^0.78t = 4*10^7/2*10^7

2/7e^0.78t = 2

e^0.78t = (2*7)/2

e^0.78t = 2

t = 2 * 1/0.78

t = 2.56 years

Hence, it'll take 2.56 years to get to 4*10^7kg

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enyata [817]

Answer:

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b). Maximum value of the function is (-3)

Step-by-step explanation:

a). f(x) = x² - 5x + 3

we have to write this function in the vertex form.

f(x) = x² - 2(2.5)x + 3

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    = (x - 2.5)²- 6.25 + 3

    = (x - 2.5)² - 3.25

So the vertex for of the function is

f(x) = (x - 2.5)² - 3.25

b). Given quadratic function f(x) = -x² - 6x + 6 is in the standard form of f(x) = ax² + bx + c.

By comparing the coefficients of both the functions,

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Here the value of a is negative, therefore, the given parabola is opening downwards.

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x=-\frac{b}{2a}

When we plug in the values,

x=-\frac{6}{2(-1)}

x = 3

Now to get the value of maximum of the function we will get the value of f(3).

f(3) = -(3)²- 6(3) + 6

f(3) = 9 - 18 + 6

f(3) = -3

Therefore, maximum value of the quadratic function is (-3).

4 0
3 years ago
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