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Usimov [2.4K]
3 years ago
14

(please zoom / zoom out if needed to see question. (: )

Mathematics
1 answer:
Katarina [22]3 years ago
3 0
Here is your answer the area of the trapezoid the diagram for question 2

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1. A right triangle LMN is given where: side MN = 8 side NL (the hypotenuse) =
inessss [21]

Step-by-step explanation:

\underline{ \underline{ \text{Given}}} :

  • Length of MN ( Base ) = 8
  • Length of NL ( Hypotenuse ) = 10

\underline{ \underline{ \text{To \: find}}} :

  • Length of LM ( Perpendicular )

\underline{ \underline{ \text{Using \: pythagoras \: theorem}}} :

\boxed{ \sf{ {Hypotenuse}^{2}  =  {Perpendicular}^{2}  +  {Base}^{2} }}

⤑ \sf{  Perpendicular =  \sqrt{ {(Hypotenuse)}^{2}  -   {(Base)}^{2}  } }

⤑ \sf{ \sqrt{ {(10)}^{2}  -   {(8)}^{2}  } }

⤑ \sf{ \sqrt{100  -  64}}

⤑ \sf{ \sqrt{36}}

⤑ \boxed{ \sf{6\: units}}

\pink{ \boxed{ \boxed{ \tt{Our \: final \: answer :  \boxed{ \underline { \tt{6 \: units}}}}}}}

Hope I helped ! ツ

Have a wonderful day / night ! ♡

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5 0
2 years ago
The Pythagorean theorem can only be used with witch type of triangle
HACTEHA [7]

Answer:

Right Triangles

Step-by-step explanation:

3 0
2 years ago
I need help with a proof. i only need number 3, 6, & 7. please help!!!
lesya692 [45]

Answer:

boottytff tgggfgv dugddcv

3 0
3 years ago
Why is cosine positive in the 4th quadrant and sine isn’t?
kari74 [83]

Answer:

Because sine can only be positive in quadrant II according to the CAST rule.

8 0
3 years ago
Helpppp!!!! brainliest to the first answer ...!
vladimir1956 [14]

Answer:

i cant read it can u do another photo

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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