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Sladkaya [172]
3 years ago
13

What are the zeros of f(x)= x•x + 3x - 10?

Mathematics
1 answer:
drek231 [11]3 years ago
5 0

Answer:

It is 9

Step-by-step explanation:

I don't knowhhrshheyd

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Find the value of y if the line through the two given points is to have the indicated slope.
Masteriza [31]
Slope is the change in y/ change in x so the equation will be:
-2= (1-y)/(-6-(-5)) -> simplify -> -2= 1-y/-1 -> multiply both sides by -1 -> 2=1-y -> simplify and -y= 1 -> y=-1 
4 0
2 years ago
If the discriminant is 22, then the roots of the quadratic equation are ________________.
Allisa [31]

Since the discriminant given has a value that is greater than zero, hence  the roots of the quadratic equation are real and distinct.

<h3>Discriminant of a quadratic equation</h3>

Quadratic equation is an equation that has a leading degree of 2. The discriminant is used to determine the nature of the equation

If D > 0 , the roots of the quadratic equation are real and distinct.

If D < 0 , the roots of the quadratic equation are complex

Since the discriminant given has a value that is greater than zero, hence  the roots of the quadratic equation are real and distinct.

Learn more on discriminant here: brainly.com/question/2507588

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4 0
1 year ago
What is the solution to 3/(2x+1) = 9/3x?
Scorpion4ik [409]

Answer:

Solution x = - 1

Step-by-step explanation:

3 / (2x+1) = 9 / 3x

Cross multiply

3(3x) = 9(2x + 1)

Distributive property

9x = 18x + 9

Subtract 18x from both sides

-9x = 9

Divide both sides by -9

x = -1

7 0
2 years ago
Does the following scenario represent independent or dependent events?
ra1l [238]
Independent
Hope this helps :)
Can I have brainliest
5 0
2 years ago
Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu
Softa [21]

<u>Answer-</u>

<em>The polynomial function is,</em>

y=x^4-10x^3+38x^2-64x+40

<u>Solution-</u>

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))   ( ∵ (3-i) is the conjugate of (3+i) )

\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)

\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)

\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)

\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)

\Rightarrow y=(x^2-4x+4)(x^2-6x+10)

\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10

\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40

\Rightarrow y=x^4-10x^3+38x^2-64x+40

Therefore, this is the required polynomial function.


4 0
3 years ago
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