Please help!!!! largest, and smallest 6 digit number divisible by 2,3,4,5,6,8,9,10

Mathematics

1 answer:

Vadim26 [7]3 years ago

3 0

Answer:

Basically it has to be divisible by 8, 9, and 10 because any number that is divisible by 2, 3, 4, 5, 6 must also be divisible by 8, 9 and 10. We know that the number has to end in 0, the sum of its digits must be divisible by 9 and the last three digits must be divisible by 8. Therefore, the smallest number is 10080 and the largest is 999360.

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Simplify. -9 -5 -7 х Y Z 2 6 3 X Y Z

krok68 [10]

Answer:

$= {x}^{ - 11} {y}^{ - 11} {z}^{ - 10}$

Step-by-step explanation:

$= \frac{ {x}^{ - 9} {y}^{ - 5} {z}^{ - 7} }{ {x}^{2} {y}^{6} {z}^{3} } \\ = {x}^{ - 9 - 2} {y}^{ - 5 - 6} {z}^{ - 7 - 3} \\ = {x}^{ - 11} {y}^{ - 11} {z}^{ - 10}$