E. none of them hope I helped
Answer:
the y intercept is 6
Step-by-step explanation:
Step 1: Add -4x to both sides.
4x+2y+−4x=12+−4x
2y=−4x+12
Step 2: Divide both sides by 2.
2y
/2 =
−4x+12
/2
y=−2x+6
Points (3,6)
x intercept is 3 and y intercept is 6
Use y=mx+b
m = 4
x = 0
y = -1
-1 = (4)(0) + b
^^^
Multiply
Assuming P (usually written in upper case) represents a force normal to a given cross section.
If a point load is applied to any point of the section, stress concentration will cause axial stress to vary.
The context of the question considers the uniformity of axial stress at a certain distance away from the point of application (thus stress concentration can be neglected).
If a force P is applied through the centroid, sections will be stressed uniformly. However, if the force P is applied at a distance "e" from the centroid, the equivalent load on the section equals an axial force and a moment Pe. The latter causes bending of the member, causing non-uniform stress.
If we assume A=(uniform) cross sectional area, and I=moment of inertia of the section, then stress varies with the distance y from the centroid equal to
stress=sigma=P/A + My/I
where P=axial force, M=moment = Pe.
Therefore when e>0, the stress varies across the section.
