To ensure the proper number amount to the bond make sure that you multiply using the numerator and the denominator as well as check over the passage because you dont know how much to use according to the results so the answers should be
(B)
Let's say that in the beginning he weighted x and at the end he weighted x-y, y being the number of kg he wanted to loose.
first month he lost
y/3
then he lost:
(y-y/3)/3
this is
(2/3y)/3=2/9y
explanation: ((y-y/3) is what he still needed to loose: y minus what he lost already
and then he lost
(y-2/9y-1/3y)/3+3 (the +3 is his additional 3 pounts)
(y-2/9y-1/3y)/3-3=(7/9y-3/9y)/3+3=4/27y+3
it's not just y/3 because each month he lost one third of what the needed to loose at the current time, not in totatl
and the weight at the end of the 3 months was still x-y+3, 3 pounds over his goal weight!
so: x -y/3-2/9y-4/27y-3=x-y+3
we can subtract x from both sides:
-y/3-2/9y-4/27y-3=-y+3
add everything up:
-19/27y=-y+6
which means
-19/27y=-y+6
y-6=19/27y
8/27y=6
4/27y=3
y=20.25
so... that's how much he wanted to loose, but he lost 3 less than that, so 23.25
ps. i hope I didn't make a mistake in counting, let me know if i did. In any case you know HOW to solve it now, try to do the calculations yourself to see if they're correct!
Answer
x = unidentified
Explanation
If 12÷3=4 and 12 = 4×3, that means 6÷0=x and x×0=6.
This isn't possible because any number divided by 0 is unidentified.
Answer:
p=2 1st is 16 p=8 second is 22 they arent equivalent
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
d = rt so to isolate r you divide both sides by t, leaving you with r=d/t
its basically speed=distance/time, or s=d/t if that's more farmiliar to you
