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DanielleElmas [232]
3 years ago
13

What is the equation of the linear function​

Mathematics
1 answer:
zhenek [66]3 years ago
3 0
Where is the picture
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At a high school, 14% of all students play a sport and 9% of all students play a
olga2289 [7]

Answer:

0.643

Step-by-step explanation:

Let, s = play a sport

c = participate in a club

P(s) = 0.14

P(s n c) = 0.09

probability that a student participates in

a club given that they also play a sport = P(c | s)

P(c | s) = P(c n s) / P(s)

P(c | s) = 0.09 / 0.14

P(c | s) = 0.64285

= 0.643

7 0
3 years ago
#11 What is 55% as a<br> fraction in simplest form?
diamong [38]

Answer:

Step-by-step explanation:

when u have a whole number as a percent and want to turn it into a fraction, simply put it over 100 and reduce if possible

55% = 55/100 which reduces to 11/20

** dont do it this way if ur percent has a decimal

4 0
3 years ago
Help!!! PLEASEEEEE <br> &amp; ps it’s the same answer choices on the other side!
Marta_Voda [28]
One unit to the left and three units up
7 0
3 years ago
Ethan opens up a new savings account. The account has a 3.5% compound interest per annum. Ethan invests £2,000 into the account
Margarita [4]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2000\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{per annum, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=2000\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=2000(1.035)^2\implies A=2142.45

3 0
3 years ago
Use the substitution method to solve the following system of equations&gt; y = - x - 4 - x + 2y = 13
Anon25 [30]
<h3>Answer:</h3>

(x, y) = (-7, 3)

<h3>Explanation:</h3>

The idea of substitution is that you write an expression for one of the variables in terms of the other variable(s), then use that expression in the place of the variable in all the other equations.

Here, your first equation gives and expression for y in terms of x. Use that expression in place of y in the second equation.

... y = -x-4 . . . . your first equation, defining y

... -x +2(-x-4) = 13 . . . . the above expression for y is put where y was in the second equation

Now, this is solved like any one-variable equation.

... -x -2x -8 = 13 . . . . eliminate parentheses

... -3x = 21 . . . . . . . . collect terms, add 8

... x = -7 . . . . . . . . . . divide by -3

... y = -(-7) -4 = 7 -4 = 3 . . . . use the expression for y to find the value of y

The solution is (x, y) = (-7, 3).

_____

<em>Comment on substitution</em>

Substitution works the same in equations as it does anywhere else in life. (Perhaps the only difference is that in equations, the substituted quantity must be <em>exactly equal</em>.) For example, in many vending machines, a dollar can be substituted for 4 quarters, and vice versa. In cooking, a small egg plus some additional liquid can be substituted for a large egg (in many cases).

The idea is that if two things are declared equivalent, either can be used in place of the other. For solving equations, this is a useful way to reduce the number of variables in an equation.

8 0
3 years ago
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