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a_sh-v [17]
3 years ago
14

For a school drama performance, student tickets cost $5 each and adult tickets cost $10 each. The sellers collected $3,570 from

512 tickets sold. If c is the number of student tickets sold, which equation can be used to find the amount of tickets sold of each type?
Mathematics
1 answer:
Ray Of Light [21]3 years ago
4 0

Answer:

The number of adult tickets sold is a=202\ tickets

The number of student tickets sold is c=310\ tickets

Step-by-step explanation:

c------>  the number of student tickets sold

a----->  the number of adult tickets sold

we know that

a+c=512 -----> equation A

5c+10a=3,70-----> equation B

therefore

the solution is

the number of adult tickets sold is a= 202 tickets

the number of student tickets sold is c= 310 tickets

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zubka84 [21]
X= cost per cherry pie
y= cost per pumpkin pie

NICOLE
1x + 9y= $60

LISA
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STEP 1
multiply Nicole's equation by -11

-11(1x + 9y)= -11($60)
multiply -11 by all terms

(-11 * x) + (-11 * 9y)= (-11 * 60)

-11x - 99y= -660


STEP 2
add Nicole's new equation from step 1 to Lisa's equation to solve for y (using the elimination method)

-11x - 99y= -660
11x + 4y= 90
the x terms "cancel out"

-95y= -570
divide both sides by -95

y= $6 per pumpkin pie


STEP 3
substitute y value into either original equation to solve for x

x + 9y= $60

x + 9(6)= 60

x + 54= 60
subtract 54 from both sides

x= $6 per cherry pie


CHECK
11x + 4y= $90
11(6) + 4(6)= 90
66 + 24= 90
90= 90


ANSWER: Each cherry pie costs $6 and each pumpkin pie costs $6.

Hope this helps! :)
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