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3 years ago

The value of a certain stock tripled. If you knew what the stock used to be worth, how would you find how much it is worth now?

Mathematics

1 answer:

katrin2010 [14]3 years ago

7 0

You would multiply what the stock used to be worth by 3 to get the answer. The answer is what the stock is worth now

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Part F<br> Describe the shape of the graph.

Leokris [45]

This graph is growing exponentially, 0.5 more each time at every point

5 0

2 years ago

Help Pls Asap!! Dont really understand the question

PolarNik [594]

Answer: B (the lower one)

Step-by-step explanation:

First let's solve for y.

x + 2y = 4

2y = -x + 4

y = -1/2x + 2

It is B since the y intercept for that graph is 2.

8 0

1 year ago

Read 2 more answers

Simone invests 1200 into two savings accounts. One account earns 4% annual interest and the other earns 5.9% annual interest. At

Allisa [31]

Answer: He invested $350 at 4% and $850 at 5.9%

Step-by-step explanation:

Let x represent the amount which he invested in the account earning 4% interest.

Let y represent the amount which he invested in the account earning 5.9% interest.

Simone invests 1200 into two savings accounts. One account earns 4% annual interest and the other earns 5.9% annual interest. This means that

x + y = 1200

The formula for determining simple interest is expressed as

I = PRT/100

Considering the account earning 4% interest,

P = $x

T = 1 year

R = 4℅

I = (x × 4 × 1)/100 = 0.04x

Considering the account earning 5.9% interest,

P = $y

T = 1 year

R = 5.9℅

I = (y × 5.9 × 1)/100 = 0.059y

At the end of 1 year, Simon earned 64.15 in interest. it means that

0.04x + 0.059y = 64.15 - - - - - - - - -1

Substituting x = 1200 - y into equation 1, it becomes

0.04(1200 - y) + 0.059y = 64.15

48 - 0.04y + 0.059y = 64.15

- 0.04y + 0.059y = 64.15 - 48

0.019y = 16.15

y = 16.15/0.019

y = 850

x = 1200 - y = 1200 - 850

x = 350

7 0

3 years ago

Suppose you invest $16000 at 9% interest and that it is compounded daily. How much will you have in 8 years?

kramer

Answer:

The amount after 8 years is $ 16,031.579

Step-by-step explanation:

Given as :

The Principal invested = $ 16000

The rate of interest compounded daily = 9 %

The time period = 8 years

Let The amount after 8 years = $ A

<u>From Compounded method </u>

Amount = Principal invested × $(1+\dfrac{\textrm Rate}{365\times 100})^{365\times \textrm Time}$

Or, Amount = 16000 × $(1+\dfrac{\textrm 9}{365\times 100})^{365\times \textrm 8}$

Or, Amount = 16000 × $(1.0002465)^{8}$

∴ Amount = $ 16,031.579

Hence The amount after 8 years is $ 16,031.579 Answer

4 0

3 years ago

Jeff works in the Klein Forest cafeteria. When A-lunch begins, he has already prepared 50lunches. He will prepare 10 lunches per

olga_2 [115]

The function is L = 10m + 50

Here, we want to find out which of the functions is required to determine the number of lunches L prepared after m minutes

In the question, we already had 50 lunches prepared

We also know that he prepares 10 lunches in one minute

So after A-lunch begins, the number of lunches prepared will be 10 * m = 10m

Adding this to the 50 on ground, then we have the total L lunches

Mathematically, that would be;

L = 10m + 50

8 0

1 year ago