Answer
8p∠-8
Step-by-step explanation:
Let h be the number of lemonade sold. If the vendor sold 86 items today and h of them are lemonade, then the rest are hot dogs, so he sold 86-h hot dogs.
When you add the number of sold lemonade and hot dogs, then you get 86 items in total:
h+(86-h)=86.
This equation is exactly the same as equation
(86-h)+h=86.
Moreover,
1. if a snack cart sells lemonade for $2, then he gets $2h for h sold lemonade;
2. if a snack cart sells hot dogs for $5, then he gets $5(86-h) for (86-h) sold hot dogs.
In total he gets $330, then
2h+5(86-h)=330.
Both these equations are true, but only first is among given options.
Answer: correct choice is B.
The values of x at wich F(x) has local minimums are x = -2 and x = 4, and the local minimums are:
<h3>
What is a local maximum/minimum?</h3>
A local maximum is a point on the graph of the function, such that in a close vicinity it is the maximum value there. So, on an interval (a, b) a local maximum would be F(c) such that:
c ∈ (a, b)
F(c) ≥ F(x) for ∀ x ∈ [a, b]
A local minimum is kinda the same, but it must meet the condition:
c ∈ (a, b)
F(c) ≤ F(x) for ∀ x ∈ [a, b]
A) We can see two local minimums, we need to identify at which values of x do they happen.
The first local minimum happens at x = -2
The second local minimum happens at x = 4.
B) The local minimums are given by F(-2) and F(4), in this case, the local minimums are:
If you want to learn more about minimums/maximums, you can read:
brainly.com/question/2118500
Given:
Carrie has 180 ft of the fencing and wishes the fence to be 4times as long as it is wide.
To Find:
The area in square feet that the fencing encloses.
Answer:
The fence encloses 3600 sq ft.
Step-by-step explanation:
Let x denote the length of the dog run and y denote the width of the dog run.
Given that the garage wall serves as one side of the dog run, we are left with 3 other sides to instal the fence.
Carrie has 180ft of fencing with her, so the sum of the lengths of the 3 sides has to be equal to 180. We can represent this in the form of an equation as
We are also given that Carrie wishes the fence to be 4 times as long as it is wide.
So,
Replacing this value into the first equation, we have
Therefore,
Thus, the length of the dog run is 120ft and the width is 30ft.
The area enclosed will be equal to the length multiplied with the width. So,
The fence encloses 3600 sq ft.
