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2 years ago

10

A pen costs twice as much as a pencil. The total cost of 1 pen and 1 pencil is $2.10. If p represents the cost of 1 pencil, whic

h equation could you use to find p
A. 2p+p=10
B. p/3=2.10
C. 2p=2.10
D. p+p=2.10

1 answer:

oksano4ka [1.4K]2 years ago

3 0

Answer:

A:2p+p=10

Step-by-step explanation:

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Step-by-step explanation:

Solve for x over the real numbers:

2 x^2 - 5 x - 12 = 0

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3 years ago

Read 2 more answers

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Answer:

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Step-by-step explanation:

We need to divide $X^3+43-49x-7x^2$ by $x^2-49$

First arrange the term $X^3+43-49x-7x^2$ in terms of ascending order of x.

Arranging we get:

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The division steps are shown in figure attached.

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Answer:

$\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }$

Step-by-step explanation:

Hello, please find below my work.

$2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0$

$\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}$

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