A rectangle is 15cm wide, and its length was increased by 2cm, if its new perimeter is 70cm. what is its original length? pls so
lve
2 answers:
Answer:
14 cm
Step-by-step explanation:
If the rectangle is 15 cm wide then the total width is 30.
So we can subtract 30 from 70,
=40
If the length is increased by 2 then there is 4 more cm added to the total length.
We can do, 40-4
=38
If 38 is the total length we do 38 ÷ 2
=14
<em>Thus,</em>
<em>The original length was 14 cm.</em>
Answer:
18cm
Step-by-step explanation:
We can set up an equation to solve this
Let's start by naming the original length before the increase x.
New length is x+2.
Formula for perimeter of a rectangle is 2L+2W=P
Plug known values in
2(x+2)+2(15)=70
Simplify
2x+4+30=70
2x+34=70
2x=36
x=18
The original length is 18cm.
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It’s C that’s the only one that works
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16x-9=39
16x=39+9
16x=48
x=48/16
x=3
Yes because you are basically taking what you are giving in the first place
12(a/3-b/4)
(12)(a/3+-1/4b)
(12)(a/3)+12(-1/4b)
ANSWER: 4a-3b
Hope it’s correct :)