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Evgen [1.6K]
4 years ago
10

Which expression is equivalent 5(2x-7) a.2x-25 b.7x-12 c.7x-12 d.10x-7 e.10x-35

Mathematics
2 answers:
Talja [164]4 years ago
5 0

Answer:

e.10x-35

Step-by-step explanation:

5(2x-7)

Distribute

10x -35

Allushta [10]4 years ago
3 0

Answer:

Your Answer is E. 10x-35

Step-by-step explanation:

Factor 10x−35

10x−35

=5(2x−7)

Answer:

5(2x−7)

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Find the point that is 3/4 of the distance P (-6,-5) to the point Q (2,7)
Zarrin [17]

Using proportions, the coordinates of the point 3/4 of the way from P to Q are: (0,4).

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

We want to find the coordinates of point M(x,y) 3/4 of the way from P to Q, hence the rule is given by:

M - P = 3/4(Q - P)

For the x-coordinate, we have that:

x + 6 = 3/4(2 + 6)

x + 6 = 6

x  = 0.

For the y-coordinate, we have that:

y + 5 = 3/4(7 + 5)

y + 5 = 9.

y = 4.

The coordinates are (0,4).

More can be learned about proportions at brainly.com/question/24372153

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8 0
1 year ago
According to the square root property, the solution set of x 2 = 25 is {±5}.<br> True<br> False
babymother [125]
I believe the correct answer is true. According to the square root property, the solution set of x^2 = 25 is {±5}. <span>The </span>square root property<span> is one method that is used to find the solutions to a quadratic (second degree) equation. This method involves taking the </span>square roots <span>of both sides of the equation. Hope this answers the question.</span>
8 0
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Read 2 more answers
tensor-on-tensor regression: riemannian optimization, over-parameterization, statistical-computational gap and their interplay
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The purpose of the tensor-on-tensor regression, which we examine, is to relate tensor responses to tensor covariates with a low Tucker rank parameter tensor/matrix without being aware of its intrinsic rank beforehand.

By examining the impact of rank over-parameterization, we suggest the Riemannian Gradient Descent (RGD) and Riemannian Gauss-Newton (RGN) methods to address the problem of unknown rank. By demonstrating that RGD and RGN, respectively, converge linearly and quadratically to a statistically optimal estimate in both rank correctly-parameterized and over-parameterized scenarios, we offer the first convergence guarantee for the generic tensor-on-tensor regression. According to our theory, Riemannian optimization techniques automatically adjust to over-parameterization without requiring implementation changes.

Learn more about tensor-on-tensor here

brainly.com/question/16382372

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7 0
2 years ago
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