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4 years ago

Find the sample space for picking a number from 1 to 3 and choosing red or white

Mathematics

1 answer:

vodomira [7]4 years ago

3 0

Answer:

The event of picking a number from 1 to 3 consists of:

Pick number 1

Pick number 2

Pick number 3

The event of choosing red or white card consists of:

Choose a red card

Choose a white card

=> The sample space for picking a number from 1 to 3 and choosing red or white card:

Pick number 1 and choose a red card

Pick number 1 and choose a white card

Pick number 2 and choose a red card

Pick number 2 and choose a white card

Pick number 3 and choose a red card

Pick number 3 and choose a white card

Hope this helps!

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3 years ago

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3 years ago

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3 years ago

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Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b

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The roots of the given polynomials exist $x=8+\sqrt{10}$ , and $x=8-\sqrt{10}$ .

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For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\$

$$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\$

$$&x=8+\sqrt{10}, x=8-\sqrt{10}$

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$ , and

$x=8-\sqrt{10}$ .

To learn more about quadratic equations refer to:

brainly.com/question/1214333

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