0.004 kilometers... so was there a typo?
Answer:
The price of pretzels in 1975 = $1.80
Step-by-step explanation:
To answer this question we are assuming the steady rate means linear.Let x be the year and y be the price.
We need to find the slope
m = (y2-y1)/(x2-x1)
= (4.80-4.05)/(2015-2005)
=.75/10
= .075
The slope is .075
We can use the point slope form of the equation
y-y1 = m(x-x1)
y-4.80 = .075(x-2015)
Distribute
y - 4.80 = .075x -151.125
Add 4.80 to each side
y - 4.80+4.80 = .075x -151.125+4.80
y = .075 x - 146.325
We want to find out how much pretzels were in 1975. Put in x=1975
y = .075(1975) -146.325
y = 148.125-146.325
y=1.80
One way to find the slope-intercept form is to plug the given values into point-slope form, y - y_{1} = m (x - x_{1}), where x_{1} and y_{1} are the coordinate points and m is the slope. Then, you solve for y.
y - y_{1} = m (x - x_{1}) Plug in the values
y - (-4) = 34 (x - 5) Fix the minus negative four
y + 4 = 34 (x - 5) Use the Distributive Property
y + 4 = 34x - 170 Subtract 4 from both sides
y = 34x - 174
The slope-intercept form of the equation that passes through (5, -4) and has a slope of 34 is y = 34x - 174.
You need to multiply the base by the height.
Answer:
Step-by-step explanation:
Using the formula for the growth of investment:
.....[1]
where,
A is the amount after t year
P is the Principal
r is the growth rate in decimal
As per the statement:
Scott invests $1000 at a bank that offers 6% compounded annually.
⇒P = $1000 and r = 6% = 0.06
substitute these in [1] we get;
⇒
Therefore, an equation to model the growth of the investment is,
