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snow_lady [41]
3 years ago
10

Only do number 19 vote you brainiest

Mathematics
1 answer:
lesya [120]3 years ago
6 0

Answer:

I think 5/12 of them are in 8th grade

Step-by-step explanation:

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6 0
3 years ago
Angle abc is dilated by a scale factor of 0.5
levacccp [35]
That isnt even a question is a mathematical statement
8 0
3 years ago
Order from smallest to largest​
Daniel [21]

Answer:

They are all one foot high so it's a trick question I think lol

Step-by-step explanation:

Hope this helped lol

5 0
3 years ago
You want to obtain a sample to estimate a population proportion. Based on previous evidence, you believe the population proporti
Ksenya-84 [330]

Answer:

We need a sample size of at least 369.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

\pi = 0.32

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

How large of a sample size is required?

We need a sample size of at least n.

n is found when M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.645\sqrt{\frac{0.32*0.68}{n}}

0.04\sqrt{n} = 1.645\sqrt{0.32*0.68}

\sqrt{n} = \frac{1.645\sqrt{0.32*0.68}}{0.04}

(\sqrt{n})^{2} = (\frac{1.645\sqrt{0.32*0.68}}{0.04})^{2}

n = 368.02

Rounding up

We need a sample size of at least 369.

5 0
4 years ago
Find the probability of rolling a 6 on a number cube and flipping heads on a coin
serious [3.7K]

Assuming that the number cube is 6 sided

6 is one number in a 6 sided cube, so the probability is: 1/6

heads is one side of the coin, with two in all: 1/2

Multiply the two fractions together

1/6 x 1/2 = 1/12

1/12 is your probability

hope this helps

4 0
4 years ago
Read 2 more answers
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