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wariber [46]
2 years ago
6

5y^2+5−4−4y^2+5y^2−4x^3 −1

Mathematics
1 answer:
vredina [299]2 years ago
6 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{4 {x}^{3}  + 6 {y}^{2} }}}}}

Step-by-step explanation:

\sf{5 {y }^{2}  + 5 - 4 - 4 {y}^{2}  + 5 {y}^{2}  - 4 {x}^{3}  - 1}

Collect like terms

⇒\sf{ 4 {x}^{3}  + 5 {y}^{2}  - 4 {y}^{2}  + 5 {y}^{2}  + 5 - 4 - 1}

⇒\sf{4 {x}^{3}  +  {y}^{2}  + 5 {y}^{2}  + 5 - 4 - 1}

⇒\sf{4 {x}^{3}  + 6 {y}^{2}  + 5 - 4 - 1}

Calculate

⇒\sf{4 {x}^{3}  + 6 {y}^{2}  + 1 - 1}

⇒\sf{4 {x}^{3}  + 6 {y}^{2} }

Hope I helped!

Best regards! :D

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A new pencil is 19 centimeters long. Levi uses it for a month. The pencil now measures 8 centimeters.
pogonyaev

Answer:

11 cm

Step-by-step explanation:

Given:

Length of new pencil = 19 cm

Length of pencil after using a month = 8 cm

Question asked:

The pencil is centimeters shorter now than when it was new = ?

Solution:

Length of new pencil = 19 cm

Length of pencil after using a month =  8 cm

The pencil is centimeters shorter now than when it was new = 19 cm -  8 cm

                                                                                                     = 11 cm

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Step-by-step explanation:

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