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Inessa [10]
3 years ago
9

Rafael's art class is 6 hours long. How long is his class in minutes?

Mathematics
2 answers:
sdas [7]3 years ago
6 0

Answer:

The art class would be 360 mins long.

Step-by-step explanation:


spin [16.1K]3 years ago
3 0

<u>Answer</u>:

360 Minutes Long

<u>Step-by-step explanation:</u>

There are 60 minutes in an hour. Multiply 60*6, and you get 360 minutes.

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Amy and her sister are making lemonade for the school dance. Their recipe makes 2 quarts of lemonade. If they make 35 times the
Anastaziya [24]
Its 17.5 gallons because 2 quarts times 35 equals 70 quarts and 17.5 gallons equals 70 quarts
7 0
3 years ago
Which would not be a step in solving 5x + 15 + 2x = 24 + 4x?
Klio2033 [76]

Answer:

A. Use the distributive property.

Step-by-step explanation:

We cannot use the distribute property because there are not parentheses to distribute a number through.

5x + 15 + 2x = 24 + 4x

We can collect the terms, and isolate the variable

8 0
2 years ago
Mike saves $42 a week for 7 weeks. During his 8-day vacation, he plans to spend $8.25 each day for snacks. Which expression show
Alla [95]
The answer is B, because you will have to multiple 42 by 7 to see how much money he will have in 7 weeks and then you will have to subtract 8 × 8.25 to see how much money he spent on his vacation.
5 0
3 years ago
How to do this does anyone know if u do i will make u brainlist
Studentka2010 [4]

Answer:

Those functions are for a graph.

Step-by-step explanation:

You can compare them by heading to a website like desmos and plugging in each function, I think they even do tables as well.

These are functions that can be graphed, I assume you know what that is, if not, look it up.

good luck

6 0
1 year ago
Read 2 more answers
Find the length of the arc of the circular helix with vector equation r(t) = 2 cos t i + 2 sin t j + tk from the point (2, 0, 0)
USPshnik [31]

\vec r(t)=2\cos t\,\vec\imath+2\sin t\,\vec\jmath+t\,\vec k

\implies\vec r'(t)=-2\sin t\,\vec\imath+2\cos t\,\vec\jmath+\vec k

\implies\|\vec r'(t)\|=\sqrt{(-2\sin t)^2+(2\cos t)^2+1^2}=\sqrt5

Then the length of the arc is

\displaystyle\int_0^{2\pi}\|\vec r'(t)\|\,\mathrm dt=\sqrt5\int_0^{2\pi}\mathrm dt=2\sqrt5\,\pi

4 0
3 years ago
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