What z score in a normal distribution has 33% of all score above it?
Answer: A z score which has 33% of all scores above it, will have 67% of all scores below it.
To find the required z score, we need to find the z value corresponding to probability 0.67.
Using the standard normal table, we have:
Therefore, the z score = 0.44 has 33% of all score above it.
Answer:
C
Step-by-step explanation:
swap y and x in the function. that is
we get x=4y+5
<em>S</em><em>o</em><em>l</em><em>v</em><em>e </em><em>for </em><em>y</em>
(x-5)/4=y
We have been given two expressions . We are asked to find the value of each.
To find 9P9, we will use permutations formula.
, where
P = Number of permutations,
n = The total number of objects in the set,
r = Number of objects being chosen from the set.
Using
To find 9C9, we will use combinations formula.
, where
C = Number of combinations,
n = The total number of objects in the set,
r = Number of objects being chosen from the set.
Using
Cancelling out , we will get:
The answers differ because order. With permutations we care about the order of the elements, while with combinations we don't.