Answer:
Distance: 8.5440037453175
Step-by-step explanation:
Distance: 8.5440037453175
Steps:
Distance (d) = √(-7 - -10)2 + (-1 - -9)2
= √(3)2 + (8)2
= √73
= 8.5440037453175
Slope and Angle:
ΔX = -7 – -10 = 3
ΔY = -1 – -9 = 8
Slope (m) =
ΔY
ΔX
=
8
3
= 2.6666666666667
θ =
arctan( ΔY )
ΔX
= 69.443954780417°
Equation of the line:
y = 2.6666666666667x + 17.666666666667
or
y =
8 x
3
+ 53
3
When x=0, y = 17.666666666667
When y=0, x = -6.625
Standard form is, hold a sec
x=2 is directix
that means it opens left or right
so we must use
(y-k)²=4p(x-h)
where vertex is (h,k) and p is distance from focus to vertex
also shortest distance from vertex to directix
the shortest distance from focus to directix is 2p
if p>0 then the parabola opens right
if p<0 then pareabola opens left
so
(-2,0) and x=2
the distance is 4
4/2=2
p=2
wait, positive or negative
focus is to the left of the directix so p is negative
p=-2
vertex is 2 to the right of the focus and 2 to the left of directix
vertex is (0,0)
so
(y-0)²=4(-2)(x-0) or
y²=-8x is da equation
not sure what form is standard tho
G(x) = 2x² - 5x + 2 = 2x² - 4x - x + 2 = 2x · x - 2x · 2 - 1 · x - 1 · (-2)
= 2x(x - 2) -1(x - 2) = (x - 2)(2x - 1)
g(x) = 0 ⇔ (x - 2)(2x - 1) = 0 ⇔ x - 2 = 0 or 2x - 1 = 0
x = 2 or x = 0.5
B. If (x = 5)
Hope this helped :)
find the perimeter of a triangle with sides 15 inches, 15 inches, and 21 inches length
To find the perimeter of a triangle we add all the sides of the triangle
The length of the sides of the triangle are given as 15 inches, 15 inches, and 21 inches
Perimeter of a triangle =
15 inches + 15 inches + 21 inches = 51 inches
So 51 inches is the perimeter
