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Evgen [1.6K]
3 years ago
14

Which values from the specified set make up the solution set of the inequality?

Mathematics
1 answer:
guapka [62]3 years ago
6 0

You may solve this problem in two ways:

If you solve the inequality explicitly (divide both sides by 4), you get

\dfrac{4n}{4} < \dfrac{16}{4} \iff n < 4

So, if n has to be stricktly less than 4, you can only choose 1, 2 and 3 as answers.

Alternatively, you can plug in all of the values you're proposed and check if the inequality holds:

If n=1, you have 4, which is true.

If n=2, you have 8, which is true.

If n=3, you have 12, which is true.

If n=4, you have 16, which is false.

So, again, only 1, 2 and 3 are solutions.

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What’s the fourth question about the big wheel please help
Lapatulllka [165]

Answer:  62.83 m

<u>Step-by-step explanation:</u>

The distance of one rotation is the perimeter of the wheel <em>(which is called "circumference" since it is in the shape of a circle)</em>

Circumference (C) = 2 π · radius (r)

C = 2π (10)

  = 20π

  ≈ 62.83

7 0
3 years ago
Find the value of k
Readme [11.4K]

Answer:

12

Step-by-step explanation:

A straight line is equal to 180. The line AB is 180 degrees. This means 174 + angle = 180 for the angle between point D and B. It must be 6 degrees. This is the same angle as the angle between point A and C.

Line CD is also straight and equal to 180. On the line are the angles, 4k + 90 + 3k + 6 = 180. Solve for k by combining like terms and then using inverse oeprations.

4k + 90 + 3k + 6 = 180

7k + 96 = 180

7k = 84

k = 12

6 0
3 years ago
What is the angel of c??
barxatty [35]
Correct answer: 50°
Subtract (65+65) from 180° and you’ll get the angle of C, which is 50°

6 0
3 years ago
Which of these sequences is a geometric sequence?
____ [38]

Answer:

if we take ratio then answer is option D

8 0
3 years ago
Factor completely 3bx2 − 9x3 − b + 3x. (b − 3x)(3x2 − 1) (b + 3x)(3x2 + 1) (b + 3x)(3x2 − 1) Prime
Daniel [21]
3bx^2-9x^3-b+3x=\boxed{3x^2}\cdot b-\boxed{3x^2}\cdot3x\fbox{-1}\cdot b\fbox{-1}\cdot (-3x)\\\\=\boxed{3x^2}(b-3x)\fbox{-1}(b-3x)=\boxed{(b-3x)(3x^2-1)}\\\\completely:\\use:a^2-b^2=(a-b)(a+b)\to3x^2-1=(x\sqrt3)^2-1^2=(x\sqrt3-1)(x\sqrt3+1)
therefore:\\3bx^2-9x^3-b+3x=(b-3x)(3x^2-1)\\=\underline{\underline{(b-3x)(x\sqrt3-1)(x\sqrt3+1)}}
6 0
3 years ago
Read 2 more answers
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