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Evgen [1.6K]
4 years ago
14

Which values from the specified set make up the solution set of the inequality?

Mathematics
1 answer:
guapka [62]4 years ago
6 0

You may solve this problem in two ways:

If you solve the inequality explicitly (divide both sides by 4), you get

\dfrac{4n}{4} < \dfrac{16}{4} \iff n < 4

So, if n has to be stricktly less than 4, you can only choose 1, 2 and 3 as answers.

Alternatively, you can plug in all of the values you're proposed and check if the inequality holds:

If n=1, you have 4, which is true.

If n=2, you have 8, which is true.

If n=3, you have 12, which is true.

If n=4, you have 16, which is false.

So, again, only 1, 2 and 3 are solutions.

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Final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

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Given problem is \sqrt[3]{x}\cdot\sqrt[3]{x^2}.

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\sqrt[3]{x}\cdot\sqrt[3]{x^2}

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Apply formula

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Hence final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

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