The initial value of the linear relationship is 5.
Solution:
- The y-intercept is the point where the line crosses at y-axis.
- The initial value of the linear function is the y-intercept.
On observing the graph, the line crosses y-axis at the point (0, 5).
So, y-intercept = 5
That is initial value = 5
Therefore the initial value of the linear relationship is 5.
Try C but im not 100% sure though
Answer:
y=15
x=43
(any variable can be used, I used x and y to make it easier to show)
Step-by-step explanation:
x+y=58
x-y=28
get x by its self
x=58-y
then subsitute into the other equation
(58-y)-y=28
58-2y=28
-2y=-30
y=15
sub. again
x+15=58
x=43
Answer:
w = (p - 21)/2
Step-by-step explanation:
Rearrange the equation so that it is equal to w.
p = 21 + 2w
p - 21 = (21 + 2w) - 21
p - 21 = 2w
(p - 21)/2 = (2w)/2
(p - 21)/2 = w
w = (p - 21)/2
