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kondor19780726 [428]
3 years ago
13

Which of these is a point-slope equation of the line that is perpendicular to y – 3 = 4(x – 10) and passes through (–3, 7)? A. y

+ 7 = –(x – 3) B. y – 7 = –4(x + 3) C. y – 7 = –(x + 3) D. y + 7 = 4(x – 3)
Mathematics
1 answer:
love history [14]3 years ago
8 0

So, we know the slope of the original equation is 4.  So the perpendicular slope is the negative reciprocal, so it's -1/4.  Then, the points have to be -3, 7.  So when we plug that into our equation, we get

Y-7 = -\frac{1}{4}(x--3)\\ Y-7=-\frac{1}{4}(x+3)

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