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sp2606 [1]
3 years ago
8

17) If your GROSS INCOME is $90,000 and you have 33% in TAXES

Mathematics
1 answer:
pychu [463]3 years ago
5 0
60,000 nnnmmmmmmmmmm
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What’s is 20x^3 divided by x^2
jolli1 [7]

Answer:

20x

Step-by-step explanation:

20 x^3/ x^2

20 x x x

----------------

x x

Cancel the x's

20 x

---------

1

20x

5 0
3 years ago
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What is the answer and how do I solve?
8_murik_8 [283]
Because it is a 90° angle and the legs are congruent, the legs intersect with the hypotenuse at the same angle, so the other, unnamed angle at the bottom left is equal to x.

Now we can state that:

2x + 90 = 180
2x = 90
x = 45
4 0
3 years ago
HELP ME PLEASE!!!
ser-zykov [4K]

parallel lines, have the same exact slope, hmmm what is the slope of y = -2/3 x + 1/3 anyway? well, low and behold, the equation is already in slope-intercept form, therefore


\bf ~~y=\stackrel{slope}{-\cfrac{2}{3}}x+\cfrac{1}{3}~~ has a slope of -2/3.


so we're really looking for a line whose slope is -2/3 and runs through 9,4.


\bf (\stackrel{x_1}{9}~,~\stackrel{y_1}{4})~\hspace{10em}slope =  m\implies -\cfrac{2}{3}\\\\\\\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-4=-\cfrac{2}{3}(x-9)\\\\\\y-4=-\cfrac{2}{3}x+6\implies y=-\cfrac{2}{3}x+10

8 0
3 years ago
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What is the scale factor solve of x
Natasha_Volkova [10]
The scale factor is 2

x = 11.5

14/7 = 2

23/x = 2

x = 11.5

3 0
3 years ago
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There are three consecutive even integers. If twice the first integer added to the second is 268,244, find all three integers.
r-ruslan [8.4K]

Answer:

89414,89416,89418

Step-by-step explanation:

Let n bet the positive integer and then 2n is an even integer because multiplying n with 2 makes it an even integer.

Now, 2n+2, 2n+4 are the next integers.

Therefore, three consecutive integers are: 2n, 2n+2, 2n+4.

It is given that twice the first integer added to the second is 268,244 that means:

2(2n)+(2n+2)=268244

4n+2n+2=268244

6n=268242

n=44707

Therefore, three consecutive integers are:

2n=89414, 2n+2=89416, 2n+4=89418

8 0
3 years ago
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