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Ilia_Sergeevich [38]
3 years ago
12

What number squared is 27?

Mathematics
2 answers:
alexdok [17]3 years ago
6 0
5.20 squared is 27.1 is that close enough?

Lunna [17]3 years ago
4 0
The answer is 5.19615242271 but if you round it to the nearest dp its 5.2
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How to solve equations with the substitution method
Paul [167]

Answer:

In a system, the substitution method is one of the 3 main ways to solve a system and can be very efficient at times.

<u>Skills needed: Systems, Algebra</u>

Step-by-step explanation:

1) Let's say we are given two equations below:

  y=4x \\ 4x-5y=-32

  We can use substitution here by substituting in for y in the second equation.   This means we put in 4x for y in the 2nd equation so we only have x variables in the equation, allowing us to solve for x.

2) Solving it out:

1) 4x-5(4x)=-32 \\ 2) 4x-20x=-32 \\3) -16x=-32 \\4)x=2\\5)y=4x = 4(2) = 8 \\ 6)y=8

We essentially substitute in that value as seen in step 1. Steps 2 and 3 are just simplifying the left side and allowing for us to solve. Step 4 is where we divide by -16 on both sides to solve for x. Step 5 and 6 show us solving for y using the value for x. We get x=2,y=8

5 0
2 years ago
Read 2 more answers
Which of these points, if any, is the midpoint of FJ?
ivanzaharov [21]

The mid-point of FJ is the number right in the middle of FJ. Find the mean of F & J. Add regardless of sign

4 + 6 = 10

10/2 = 5

Add 5 to -4

5 + -4 = 1

H is your midpoint

True. As long as AB and BC are on the same line, AB + BC = AC

hope this helps

4 0
3 years ago
A bacteria colony increases in size at a rate of 4.0581e1.6t bacteria per hour. If the initial population is 36 bacteria, find t
Harrizon [31]

Answer:

1560

Step-by-step explanation:

The rate of Increase of the population (P) of the bacteria is given as:

\frac{dP}{dt} =4.058e^{1.6t}

dP =4.058e^{1.6t}}dt\\Taking\: Integrals\\\int dP =4.058 \int e^{1.6t}dt\\P(t)=\frac{4.058}{1.6} (e^{1.6t} +K)\\P(t)=2.53625 (e^{1.6t} +K)

Where k is a constant of Integration.

At t=0, P(t)=36

36=2.53625 (e^{1.6*0} +K)\\36=2.53625 (e^{0} +K)\\36=2.53625 (1 +K)\\36=2.53625 +2.53625K\\K=13.19

Therefore:

P(t)=2.53625 (e^{1.6t} +13.19)\\At \: t=4\\P(4)=2.53625 (e^{1.6*4} +13.19)\\=1559.88\\P(4)=1560

3 0
3 years ago
Why is it important to check all solutions to radical equations?
aleksklad [387]
Hello.

The solutions found to radical equations are not necessarily viable. They sometimes result in inequalities, and have to be checked.

Hope I helped.
4 0
3 years ago
Read 2 more answers
Someone help please?
alukav5142 [94]

Answer:

form 1 question????????

3 0
2 years ago
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