90. To get to this answer, you would multiply 6 X 10 and 3 X 10. You would then add the products: 60 + 30 = 90.
Answer:
Option 2: 
Step-by-step explanation:
Given:
From the triangle shown below;
A triangle QRS with angle QRS = 90°, ∠QSR = 30°.
Side QR = 5, SQ = 10 and RS = 5√3
Now, we know from trigonometric ratio that,

Here, opposite side of angle QSR is QR and Hypotenuse is the side opposite angle QRS which is SQ. Therefore,

Therefore, the value of sine of 30° is one-half. So, second option is correct.
Answer:
C = (A*P - 8.4Y -330T + 200I) / 100
Step-by-step explanation:
P = (8.4Y + 330T + 100C -200I ) / A
now we have to calculate completed passes C for given P, Y, T, I, A
A*P = 8.4Y + 330T -200I +100C
100C = A*P - 8.4Y - 330T + 200I
C = (A*P - 8.4Y -330T + 200I) / 100
I just solved the equation for C
By Pythagoras AB^2 = 12^2 - 6^2 = 108
AB = sqrt 108 = 10.39 to nearest hundredth
The perpendicular from M to DC will be parallel and equal to AB so it = 10.39.
Also AB^2 = CB * DB
108 = 6 * DB
DB = 108/6 = 18
so DC = 18-6 = 12
MD^2 = (1/2*12)^2 + 108 = 144
so MD = 12
Answer:
18p = # of photographs Dillon has