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Kipish [7]
3 years ago
9

Help plz:)))I’ll mark u Brainliest

Mathematics
1 answer:
Shtirlitz [24]3 years ago
5 0

Answer:

height of the cone B is 12 cm

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Help on area of composite figures
balandron [24]
 break it up into simpler shapes. See the photo.
There is:
trapezoid
A = 0.5(3.2+6.5)4.5
= 21.825

triangle
A = 0.5(2.7)4.5
= 6.075

rectangle
A = 1.8(4.5)
= 8.1

Total Area = 21.825 + 6.075 + 8.1
= 36

7 0
3 years ago
The ratio of minutes to dry and minutes to
Mnenie [13.5K]

Answer:

56:42 (i hope this is right)

Step-by-step explanation:

I divided 56 and 4 which makes 14. Then I multiplied 14 and 3 to get 42. So 56 by 42.

3 0
3 years ago
Please help! I just need the second question answered given the first is correct.
Nataliya [291]

Answer: 0.970 ??

Step-by-step explanation:

5 0
3 years ago
A telemarketer is successful at getting people to donate money for her organization in 55% of all calls she makes. She must get
Tems11 [23]
An interesting twist to a binomial distribution problem.

Given:
p=55%=0.55 for probability of success in solicitation
x=4=number of successful solicitations
n=number of calls to be made
P(x,n,p)>=89.9%=0.899  (from context, it is >= and not =, which is almost impossible)

From context of question, all calls are assumed independent, with constant probability of success, so binomial distribution is applicable.

The number of successes, x, is then given by
P(x)=C(n,x)p^x(1-p)^{n-x}where
p=probability of success
n=number of trials
x=number of successesC(n,x)=\frac{n!}{x!(n-x)!}

Here we need n such that
P(x,n,p)>=0.899
given
x>=4, p=0.55, which means we need to find

Method 1: if a cumulative binomial distribution table is available, we can look up n=9,10,11 and find
P(x>=4,9,0.55)=0.834
P(x>=4,10,0.55)=0.898
P(x>=4,11,0.55)=0.939
So she must make (at least) 11 calls to make sure the probability of meeting her quota is 89.9% or more.

Method 2: using technology.
Similar to method 1, we can look up the probabilities directly, for n=9,10,11
P(x>=4,9,0.55)=0.834178
P(x>=4,10,0.55)=0.8980051
P(x>=4,11,0.55)=0.9390368

Method 3: using simple calculator
Here we need to calculate the probabilities for each value of n=10,11 and sum the probabilities of FAILURE S=P(0,n,0.55)+P(1,n,0.55)+P(2,n,0.55)+P(3,n,0.55)
so that the probability of success is 1-S.
For n=10,
P(0,10,0.55)=0.000341
P(1,10,0.55)=0.004162
P(2,10,0.55)=0.022890
P(3,10,0.55)=0.074603
So that
S=0.000341+0.004162+0.022890+0.074603
=0.101995
and Probability of getting 4 successes (or more) 
=1-S
=0.898005, missing target by 0.1%

So she will have to make 11 phone calls, bring up the probability to 93.9%.  The work is similar to that of n=10.
8 0
3 years ago
Plot 9/10 and 1 2/5 on the number line below​
HACTEHA [7]
First one is 9/10 second is 1 2/5

6 0
3 years ago
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