All categories

4 years ago

If f(x) x^2-3x find f(-1.8

Mathematics

1 answer:

ICE Princess25 [194]4 years ago

8 0

The answer = 2.16
Good luck

You might be interested in

~SHOW ALL OF YOUR WORK~ Find the volume of this figure. Round to the nearest tenth.

ASHA 777 [7]

Answer:

Rounded to the Nearest Tenth is V=769.3π

Step-by-step explanation:

The diameter of the figure is 7, so the radius is 3.5. So, the radius is 3.5

The height is 20

Formula for cylinders= V= Bh or V=πr2h

I will use V=πr2h

V=π(3.5)²(20)

V=π(12.25)(20)

V=π(245)

V=769.3π

Hope this helped

6 0

3 years ago

A landscape designer is designing a flower garden that is shaped like a parallelogram. The length of the edges of the garden alo

Anika [276]

I don’t know that’s a hard one

8 0

3 years ago

Point A(-7, - 2) is rotated 270 counterclockwise and then shifted down 3 units.

Andreas93 [3]

It would be C. You make the points into (-2,7) then subtract 3 from your new points and you get (-2,4)

7 0

3 years ago

Michael recorded the color of each car that passed by his office. He saw 30 blue cars and 40 green cars. What is the experimenta

Alex73 [517]

Answer:

3/7

Step-by-step explanation:

4 0

4 years ago

To find the equation of a line, we need the slope of the line and a point on the line. Since we are requested to find the equati

Ad libitum [116K]

Answer:

$m = \frac{1}{12}$

Step-by-step explanation:

Given

$(x,y) = (36,6)$

$f(x) = \sqrt x$ ----- the equation of the curve

Required

The slope of f(x)

The slope (m) is calculated using:

$m = \lim_{h \to 0} \frac{f(a + h) - f(a)}{h}$

$(x,y) = (36,6)$ implies that:

$a = 36; f(a) = 6$

So, we have:

$m = \lim_{h \to 0} \frac{f(a + h) - f(a)}{h}$

$m = \lim_{h \to 0} \frac{f(36 + h) - 6}{h}$

If $f(x) = \sqrt x$ ; then:

$f(36 + h) = \sqrt{36 + h}$

So, we have:

$m = \lim_{h \to 0} \frac{\sqrt{36 + h} - 6}{h}$

Multiply by: $\sqrt{36 + h} + 6$

$m = \lim_{h \to 0} \frac{(\sqrt{36 + h} - 6)(\sqrt{36 + h} + 6)}{h(\sqrt{36 + h} + 6)}$

Expand the numerator

$m = \lim_{h \to 0} \frac{36 + h - 36}{h(\sqrt{36 + h} + 6)}$

Collect like terms

$m = \lim_{h \to 0} \frac{36 - 36+ h }{h(\sqrt{36 + h} + 6)}$

$m = \lim_{h \to 0} \frac{h }{h(\sqrt{36 + h} + 6)}$

Cancel out h

$m = \lim_{h \to 0} \frac{1}{\sqrt{36 + h} + 6}$

$h \to 0$ implies that we substitute 0 for h;

So, we have:

$m = \frac{1}{\sqrt{36 + 0} + 6}$

$m = \frac{1}{\sqrt{36} + 6}$

$m = \frac{1}{6 + 6}$

$m = \frac{1}{12}$

Hence, the slope is 1/12

7 0

3 years ago