Which of the following is equal to 19.4?

I have a question that says " jada has read 3/5 of a book. She has read 75 pages so far. How many pages are in the whole book?"

jok3333 [9.3K]

Answer and Step-by-step explanation:

To solve, we would multiply by the reciprocal of the portion Jada has read, and multiply that number to 75.

The reciprocal means the the value, but flipped, so $\frac{3}{5}$ will become $\frac{5}{3}$ .

Now we do 75 times $\frac{5}{3}$ /

$\frac{75 * 5}{3} \\\\\\\\\frac{375}{3} \\\\\\\\125$

So, there are 125 total pages in the book.

#teamtrees #PAW (Plant And Water)

3 0

2 years ago

Land needs to order supplies for the upcoming month. Her

Dahasolnce [82]

60 of each item

Step-by-step explanation:

5 boxes of pencils, 6 boxes of markers, 15 boxes of notebooks, 10 boxes of erasers, and four boxes of folders

6 0

3 years ago

Read 2 more answers

You are on the high school basketball team. The ball you use has a diameter of 9 inches. What is the volume of the ball? Use 3.1

nlexa [21]

Answer:

63.6

Step-by-step explanation:

5 0

2 years ago

A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we

weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean weighing of specimen = $\frac{3.412+3.416+3.414}{3}$ = 3.414 g

$\sigma$ = population standard deviation = 0.001 g

n = sample of specimen = 3

$\mu$ = population mean

Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

99% confidence interval for $\mu$ = [ $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } }$ , $3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } }$ ]

= [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0

2 years ago

Pls help need it ASAP can’t figure it out

Pie

Answer:

-25

Step-by-step explanation:

10^2 ÷ -2^2 = -25

That's why the answer is -25.

4 0

2 years ago