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Harrizon [31]
3 years ago
9

What is the area of the triangle that is 30 m base in the height of 12 m in a straight line of 13

Mathematics
1 answer:
Reika [66]3 years ago
3 0

Answer:

60

Step-by-step explanation:

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Mr. Sen wants to treat a group of friends either to the movies or to a hockey game for his birthday. Both the theater and the ho
monitta

Answer:

there's no numbers to answer this question

Step-by-step explanation:

I apologize but all the information and table is gone there is no way to answer this for you

8 0
2 years ago
How much of 30% HCI and 45% HCI would be needed to mix and produce 50 liters of 35% HCI
VladimirAG [237]

Answer:

  • 33 1/3 liters of 30%
  • 16 2/3 liters of 45%

Step-by-step explanation:

Let x represent the liters of 45% solution needed. Then the amount of HCl in the mix is ...

  0.45x +0.30(50 -x) = 0.35(50)

  0.15x = 0.05(50) . . . . . simplify, subtract 0.30(50)

  x = (0.05/0.15)(50) = 50/3 = 16 2/3 . . . liters of 45% HCl

33  1/3 liters of 30% and 16 2/3 liters of 45% HCl are needed.

_____

<em>Comment on the solution</em>

You may notice that the general solution to a mixture problem of this sort is that the fraction of the mix that is the highest contributor is ...

  (mix % - low %) / (high % - low %) = (.35 -.30) / (.45 -.30) = .05/.15 = 1/3

5 0
3 years ago
What is the sum of 1/8 + 5/16 + 3/8<br><br> 9/32<br> 13/32<br> 9/16<br> 13/16
den301095 [7]

11/16 sorry I’m stxxupid

6 0
3 years ago
Read 2 more answers
The area of the shaded segment is 100cm^2. Calculate the value of r.
Reil [10]
Hello, 

The formula for finding the area of a circular region is: A=  \frac{ \alpha *r^{2} }{2}

then:
A_{1} = \frac{80*r^{2} }{2}

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

cos(40)= \frac{h}{r}  \\  \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)

Now we can find its area:
A_{2}=2* \frac{b*h}{2}  \\  \\ A_{2}= [r*sen(40)][r*cos(40)]\\  \\A_{2}= r^{2}*sen(40)*cos(40)

The subtraction of the two areas is 100cm^2, then:

A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm

Answer: r= 1.59cm
7 0
2 years ago
Read 2 more answers
I NEED HELP ASAP 50 POINTS!!!
Rudiy27

Answer:

Step-by-step explanation:

Standard form:  -4x³ + x + 7

Name of the polynomial:

Based on number of terms:  3 terms are there.

Trinomial

Based on degree:

Degree of the polynomial is 3

Cubic polynomial

5 0
2 years ago
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