The answer is
A. No, because 1 x-value corresponds to 2 different y-values
Answer:
305.12 square inches
Step-by-step explanation:
The picture of the question in the attached figure
we know that
The area of the window is equal to the area of a rectangle, plus the area of two quarter circles plus the area of the smaller square between the two upper corners
so
Find the area of rectangle

Find the area of the two quarter circle
![A=2[\frac{1}{4}(3.14)(4^2)]](https://tex.z-dn.net/?f=A%3D2%5B%5Cfrac%7B1%7D%7B4%7D%283.14%29%284%5E2%29%5D)

Find the area of the smaller square between the two upper corners

The total area is equal to

Answer:
<h2>D. Quadrant III</h2>
Step-by-step explanation:
Quadrant in coordinate geometry is divided into four parts which is called Quadrants.
Quadrants I (x, y)
Quadrants II (-x, y)
Quadrants III (-x, -y)
Quadrants IV (x, -y)
so W(-3, -9) both are negatives so its lie on Quadrants III
Hello!
Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.
Horizontal asymptotes are determined by:
1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.
2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.
3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.
To find the vertical asymptote:
2x² - 10 = 0
2(x² - 5) = 0
(x - √5)(x + √5) = 0
x = √5 and x = -√5
Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.
To find the horizontal asymptote:
If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.
Therefore, the horizontal asymptote of this function is y = 0.
Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0