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Verdich [7]
3 years ago
9

If 50% of 120% of 30% of a number is 108,what is the number

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

600

Step-by-step explanation:

Of means multiply and is means equals

50% * 120% * 30% *N= 108

Change to decimal form

.50 * 1.20 * .30 * N = 108

Multiply

.18 N = 108

Divide each side by .18

.18N /.18 = 108/.18

N =600

miv72 [106K]3 years ago
5 0

Hello from MrBillDoesMath!

Answer:

The number is 600

Discussion:

Percent means "per 100" or divided by 100. The Question is equivalent to

50 % * 120% * 30% * x = 108

where x is the number to be found. This is equivalent to

(50/100)* (120/100) * (30/100) * x = 108   => simplify fractions

(1/2)       * (12/10)  *    ( 3/10) * x      = 108   =>  as 3 * 12 = 36

36/ (2 * 10* 10) * x  = 108                           =>  36 * 3 = 108. Divide by 36

1/(200) *x = 108/36 = 3                             => multiply both sides by 200

x = 3 * 200 = 600

Thank you,

MrB

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3 years ago
Which is the quotient of 11/12 divide 5/7 <br> a.55/84 <br> b.16/19 <br> c.77/84 <br> d.1 17/60?
Lyrx [107]
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3 years ago
If 120% is £360, what is 100%?
Lunna [17]

Answer:

300

Step-by-step explanation:

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5 0
2 years ago
X= 7 4. Find the equation of a line passing through (5, -6) perpendicular (b) 3x + 5y = (d) 7x - 12y (f) x = 7 (a) 2x + y = 12 (
goldfiish [28.3K]

Given data:

The first set of equations are x+y=4, and x=6.

The second set of equations are 3x-y=12 and y=-6.

The point of intersection of first set of te equations is,

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The first point is (6, -2).

The point of intersection of second set of te equations is,

3x-(-6)=12

3x+6=12

3x=6

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The second point is (2, -6).

The equation of the line passing through (6, -2) and (2, -6) is,

\begin{gathered} y-(-2)=\frac{-6-(-2)}{2-6}(x-6) \\ y+2=\frac{-6+2}{-4}(x-6) \\ y+2=x-6 \\ y=x-8 \end{gathered}

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6 0
11 months ago
Explain whether the following given sets are closed under addition:
Ivan

Answer:

Step-by-step explanation:

a) Yes.

\forall\ a,b\ \in\ B,\ a+b\in B\ (since\ 0+0=0)

b) Yes

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c) Yes

\forall n\ \in\ \mathbb{N}: \Longrightarrow\ n+1 \in\ \mathbb{N}\\

d) No

3\in V , 3+3=6\notin V\\

7 0
3 years ago
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