| u | = √(2² + (-1²)) = √5
| v | = √ ( 1² + (-8)² = √65
cos (u,v) = ( u * v ) / (| u | * | v |) =
(2 * 1 + ( -1 ) * ( - 8 )) / √5 √ 65 = (2 + 8) / √5 √65 = 10 / (√5 √ 65 )
The length of a larger diagonal:
d 1² = | u |² + 2 |u| |v| + | v |² = 5 + (2 √5 √65 * 10 / √5 √65 )+65
d 1² = 70 + 20 = 90
d 1 = √ 90 = 3√10
d 2² = 70 - 20 = 50
d 2 = √50 = 5√2
Answer:
The lengths of the diagonals are: 3√10 and 5√2 .
It would help if we represent the information in form of two-ways table as shown below
The number of students who are not on probation is 104 students
There are 23 students who are not on probation and is satisfied is 81 students
The probability of students not on probation and is satisfied is 81/104
Https://youtu.be/Qo1_xkv2w_M
Answer:
Answer is the 72.02 cm³ .I hope it's helpful to you.
Move all terms not containing x to the right side of the equation
x=9