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Verdich [7]
3 years ago
9

If 50% of 120% of 30% of a number is 108,what is the number

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

600

Step-by-step explanation:

Of means multiply and is means equals

50% * 120% * 30% *N= 108

Change to decimal form

.50 * 1.20 * .30 * N = 108

Multiply

.18 N = 108

Divide each side by .18

.18N /.18 = 108/.18

N =600

miv72 [106K]3 years ago
5 0

Hello from MrBillDoesMath!

Answer:

The number is 600

Discussion:

Percent means "per 100" or divided by 100. The Question is equivalent to

50 % * 120% * 30% * x = 108

where x is the number to be found. This is equivalent to

(50/100)* (120/100) * (30/100) * x = 108   => simplify fractions

(1/2)       * (12/10)  *    ( 3/10) * x      = 108   =>  as 3 * 12 = 36

36/ (2 * 10* 10) * x  = 108                           =>  36 * 3 = 108. Divide by 36

1/(200) *x = 108/36 = 3                             => multiply both sides by 200

x = 3 * 200 = 600

Thank you,

MrB

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Nady [450]
Commutative and Distributive. And also MDAS for basic operations

Commutative Property is the property in which you can move around numbers in numerical operations like, addition and multiplication while retaining their result. In contrast to subtraction and division in which position is an important factor for every result, here it is regardless. Why might you want to use this property?<span>Well, most importantly it suits the operation of addition and hence, to ensure the arrangement of the number is in symmetric proportion to its counterpart such as 3 + 2=2 + 3. Or rather, understanding that the equations in both sides are but the same and equal in sum. Thus, this is much more usable or will make more sense if used in a larger scale of complex equations and integers.<span>

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Distributive Property by allotting: 2(3) x 107 = 642<span> </span>

4 0
3 years ago
Need help with this please!!!
BARSIC [14]
I don't like dividing polynomials so I'm going to set x=1 and try them out.

(1-2-14+3)/4 = -3

Of the choices, only D gives -3 when x=1

~~~~~~~~~~~~~~~~~~~~~~

That's as much test-taking as math.  If we were to divide


             x^2 - 5x + 1
          -------------------------------
x + 3 |   x^3 - 2x^2 - 14x + 3
             x^3 + 3x^2
                      -5x^2 - 14x
                       5x^2 + 15x
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                                      x + 3

More work, still choice D


5 0
3 years ago
Find the missing value for the radioactive isotope. (Round your answer to two decimal places.)
Otrada [13]

Answer:

1.1289 grams ( approx )

Step-by-step explanation:

Since, the final quantity of an element which has half life of n periods,

A=P(\frac{1}{2})^{\frac{t}{n}}

Where,

P = initial quantity,

t = total number of periods,

Here, A = 1 gram, t = 1000 years, n = 5715 years,

By substituting the values,

1 = P(\frac{1}{2})^\frac{1000}{5715}

\implies P = 2^\frac{1000}{5715}\approx 1.1289 ( using calculator )

Hence, the initial quantity would be 1.1289 grams ( approx )

4 0
3 years ago
Please help, I can't figure out how to set this up. There's supposed to be 2 equations.
Valentin [98]

Hello from MrBillDoesMath

Answer:     + 4/7,   6 (13/14)

Discussion:

Let L be the larger of the two numbers and S the smaller of the two. Then the first sentence translates into this:


-6L - L = -4  =>

-7L = -4        =>          (divide both sides by -7)

L = - (-4)/(-7) = + 4/7       (*)


The second sentence translates to

2 (L + S) = 15  =>               (divide both sides by 2)

(L +S) = 15/2  =>                (subtract L from each side)

S = 15/2 - L = 15/2 - 4/7    (using (*) above)

So

S = 15*7/(2*7) - (4*2)/(7*2)       (combine over common denominator of 14)

S = 105/14 - 8/14 = 97/14 = 6 13/14

Something is crazy here!    While 2(L +S) = 15  -- check it out -- our larger number L ( =4/7) is actually smaller than the S number (6 13/14)!  Maybe I should have called them Y and X, respectively, as you suggested!

Thank you,

Mr. B


7 0
3 years ago
Determine the slope ....................
snow_lady [41]

Answer:

2

Step-by-step explanation:

5 0
3 years ago
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