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TEA [102]
3 years ago
13

The sum of three consecutive integers is 108. Which equation would be used to solve this word problem? (HINT: The equation has b

een simplified some...) a. 3x + 3 = 108 b. 3x = 108 c.3(x+3) = 108 d. 3x + 1 = 108
Mathematics
1 answer:
anastassius [24]3 years ago
5 0
The correct answer would be B. 3x= 108
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2 3/5 1 5/6 2 1/3 in order from least to greatest
emmasim [6.3K]

Answer:

1 5/6, 2 1/3, 2 3/5

Step-by-step explanation:D

4 0
3 years ago
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I am having trouble with this problem. I need to find the lengths of this right triangle. How would you do this?
podryga [215]
You labeled the triangle wrong sides 'a' and 'b' are supposed to be the sides that make the right angle.  the other side is called the hypotenuse which is the longest side which you should have labeled 'c'

so Pythagorean theorem says
a^2+b^2=c^2
so
(2x+1)^2+(11x+5)^2=(12x+1)^2
distribute
(4x^2+4x+1)+(121x^2+110x+25)=(144x^2+24x+1)
add like terms
125x^2+114x+26=144x^2+24x+1
subtract 125x^2 from both sides
114x+26=19x^2+24x+1
subtract 114x from both sides
26=19x^2-90x+1
subtract 26 from both sides
0=19x^2-90-25
factor
(x-5)(19x+5)=0
therefor x-5=0 and/or 19x+5=0
so
x-5=0 add 5 to both sides
x=5
19x+5=0
subtract 5 from both sides
19x=-5
divide both sides by 19
x=-5/19
since side legnths can't be negative, we can cross this solution out

so x=5
subtitute
1+2x
1+2(5)
1+10=11
side a=11

11x+5
11(5)+5
55+5=60
side b=60

12x+1
12(5)+1
60+1=60
side c=61
add them all up
side a+b+c=11+60+61=132=total legnth
5 0
3 years ago
How much is 3 over 15 plus 1 over 3
REY [17]

Answer:

8/15

Step-by-step explanation:

Well to add fractions you have to have the same denominator so you would multiply your 1/3 by 5 to be 5/15 then you can add.

3/15 + 5/15 = 8/15

4 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP<br> If Someone read the book "Gryphon" by Charles Baxter please can you help me.
Neko [114]
If someone reads the book (Gryphon) by Charles baxter what???
4 0
3 years ago
Find the interquartile range of the data.
likoan [24]

The answer is 14. Here is how I work it out.


First we are going have to identify quartile 1 and quartile 3.


So after putting the numbers in order from least to greatest mark the number with a half way point.

This is optional but it will help us spot the sections better.


31,33,35,41,43,|46,48,49,49,50

Next put parentheses around the remaining groups of numbers.

(31,33,35,41,43,)|(46,48,49,49,50)


For the next step we have to find the median of each group.


(31,33,35,41,43,)|(46,48,49,49,50)


The median of each group, are called the quartiles, the median of the lower half is quartile 1, and the median of the upper half is quartile 3.


Now subtract quartile 1 from quartile 3.


49 – 35 = 14


So the interquartile range of this data set is 14.

4 0
3 years ago
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