This construction shows the creation of tangents to the circle with a point outside the circle.
The next step would be the connect the point p with the two intersection points of the arcs on the circle.
Hope this helps :)
Answer:
y = -3/2x + 3
Step-by-step explanation:
We can get 2 points from the graph
(0,3)
(2,0)
from (0,3) we know that the b in the equation is 3
now to calculate m or slope we use
= -3/2
so we plug our m and b into y = mx + b and get
y = -3/2x + 3