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3 years ago

How much is 3 over 15 plus 1 over 3

Mathematics

2 answers:

Alina [70]3 years ago

5 0

1 over 3 would change to 5 over 15 to make the denominators equal then you add the numerators and you get 8 over 15

REY [17]3 years ago

4 0

Answer:

8/15

Step-by-step explanation:

Well to add fractions you have to have the same denominator so you would multiply your 1/3 by 5 to be 5/15 then you can add.

3/15 + 5/15 = 8/15

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The product of 6287×543 = 3,413,841 . What is the value of 628.7×5.43

lys-0071 [83]

Answer:

3,413.841

Step-by-step explanation:

you times 628.7 by 5.43 and then you get your answer

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3 years ago

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Simplify 6s^5t x s^4t^2. 6 points on the line please help me

Ghella [55]

Answer:

6s9t3

—————

Step-by-step explanation:

Step 1 :

Simplify —

Equation at the end of step 1 :

(((6 • (s5)) • —) • s4) • t2

Step 2 :

Equation at the end of step 2 :

(((2•3s5) • —) • s4) • t2

Step 3 :

Multiplying exponential expressions :

3.1 s5 multiplied by s4 = s(5 + 4) = s9

Equation at the end of step 3 :

6s9t

———— • t2

Step 4 :

Multiplying exponential expressions :

4.1 t1 multiplied by t2 = t(1 + 2) = t3

3 0

3 years ago

At a bookstore, you buy a calendar for $5 and some books for $3 each. You spend a total of $26. How many

Likurg_2 [28]

You buy 7 books

3b+5=26
*subtract 5 to the 26 side*
3b=21
Now divide 21 by 3
B=7
So there are 7 books bought. ^^

7 0

3 years ago

In 1990, 23.8% of 18-24 year-olds in Biddeford, Maine were attending college. About 10 years later, a random sample of 610 18-24

Vlada [557]

Answer:

There is enough evidence to support the claim that the percentage of residents attending college in that age-group is greater than 23.8%

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 610

p = 23.8% = 0.238

Alpha, α = 0.01

Number of 18-24 year-old attending college , x = 178

First, we design the null and the alternate hypothesis

$H_{0}: p = 0.238\\H_A: p > 0.238$

This is a one-tailed(right) test.

Formula:

$\hat{p} = \dfrac{x}{n} = \dfrac{178}{610} = 0.2918$

$z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Putting the values, we get,

$z = \displaystyle\frac{0.2918-0.238}{\sqrt{\frac{0.238(1-0.238)}{610}}} = 3.1201$

Now, we calculate the p-value from the table.

P-value = 0.0009

Since the p-value is lower than the significance level, we fail to accept the null hypothesis and reject the null hypothesis.

Conclusion:

Thus there is enough evidence to support the claim that the percentage of residents attending college in that age-group is greater than 23.8%

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4 years ago

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asambeis [7]

Answer:

The correct graph is A.

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