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grigory [225]
3 years ago
15

What are the steps for using a compass and straightedge to construct a square? Drag and drop the steps in order from start to fi

nish.
1.Construct a line perpendicular to line m through point F. Label a point on this line as point G.
2.Use a straightedge to draw line m and label a point on the line as point F.
3.Without changing the compass width, place the compass point on point H and draw an arc in the interior of ∠HFK .
4.Use the straightedge to draw JH¯¯¯¯¯ and JK¯¯¯¯¯.
5.With the compass open to the desired side length of the square, place the compass point on point F and draw an arc on line m and an arc on FG←→ . Label the points of intersection as points H and K.
6.Keeping the same compass width, place the compass on point K and draw an arc in the interior of ∠HFK to intersect the previously drawn arc. Label the point of intersection as point J.

Mathematics
2 answers:
Mazyrski [523]3 years ago
5 0

For those of you who are doin the test rn here are the answers to all of them. Hope this helps! ;) I did the quiz

Aleks04 [339]3 years ago
3 0
<span>The steps for using a compass and straightedge to construct a square are given as follows:

1. </span><span>Use a straightedge to draw line m and label a point on the line as point F

2. </span><span>Construct a line perpendicular to line m through point F. Label a point on this line as point G.

3. </span><span>With the compass open to the desired side length of the square, place the compass point on point F and draw an arc on line m and an arc on FG←→ . Label the points of intersection as points H and K.

4. </span><span>Without changing the compass width, place the compass point on point H and draw an arc in the interior of ∠HFK.

5. </span><span>Keeping the same compass width, place the compass on point K and draw an arc in the interior of ∠HFK to intersect the previously drawn arc. Label the point of intersection as point J.

6. </span><span>Use the straightedge to draw JH¯¯¯¯¯ and JK¯¯¯¯¯.
</span>
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I NEED HELP PLEASEEE
Gwar [14]

Answer:

b = \sqrt{333}

Step-by-step explanation:

1. We can use the Pythagorean Theorem to find the missing side, b.

  • 14^2 + b^2 = 23^2

2. (Solving)

Step 1: Simplify both sides of the equation.

  • (14*14)+b^2 =(23*23)
  • 196 + b^2 = 529

Step 2: Subtract 196 from both sides.

  • 196 + b^2 - 196 = 529 - 196
  • b^2 = 333

Step 3: Take square root of both sides.

  • \sqrt{b^2} = \sqrt{333}
  • b = \sqrt{333}

Step 4: Check if solution is correct.

  • 14^2 + \sqrt{333^2} = 23^2
  • (14*14)+(\sqrt{333} *\sqrt{333})=23*23
  • 196 + 333 = 529
  • 529 = 529

Therefore, b = \sqrt{333}.

6 0
2 years ago
Read 2 more answers
The table below shows the number of cups of coffee people drink a day
Effectus [21]

The mean of a distribution is the sum of the data elements divided by the count of the dataset.

<em>The mean of the distribution is 4</em>

The complete table is given as

\left[\begin{array}{cc}People & Frequency &0 - 2 & 5 & 3 - 5 & 25 & 6 - 8 & 5\end{array}\right]

The complete question requires that, we calculate the mean of the dataset

First, we calculate the class midpoint

This is the average of the class interval

<u />

<u>For interval 0 - 2, </u>

x_1 = \frac{0 + 2}{2} = 1

<u>For interval 3 - 5,</u>

x_2 = \frac{3 + 5}{2} = 4

<u>For interval 6 - 8</u>

x_3 = \frac{6 + 8}{2} = 7

So, the table becomes

\left[\begin{array}{ccc}People & x & Frequency &0 - 2 &1 & 5 & 3 - 5 & 4& 25 & 6 - 8& 7 & 5\end{array}\right]

The mean is then calculated as:

\bar x = \frac{\sum fx}{\sum f }

This gives

\bar x = \frac{5 \times 1 + 25 \times 4 + 5 \times 7}{5 + 25 + 5}

\bar x = \frac{140}{35}

\bar x = 4

Hence, the mean of the distribution is 4

Read more about mean at:

brainly.com/question/17060266

4 0
1 year ago
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The editor of a textbook publishing company is deciding whether to publish a proposed textbook. Information on previous textbook
kogti [31]

Answer:

34.86% probability that it will be huge​ success

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Receiving a favorable review.

Event B: Being a huge success.

Information on previous textbooks published show that 20 % are huge​ successes

This means that P(B) = 0.2

99 % of the huge successes received favorable​ reviews

This means that P(A|B) = 0.99

Probability of receiving a favorable review:

20% are huge​ successes. Of those, 99% receive favorable reviews.

30% are modest​ successes. Of those, 70% receive favorable reviews.

30% break​ even. Of those, 40% receive favorable reviews.

20% are losers. Of those, 20% receive favorable reviews.

Then

P(A) = 0.2*0.99 + 0.3*0.7 + 0.3*0.4 + 0.2*0.2 = 0.568

Finally

P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.2*0.99}{0.568} = 0.3486

34.86% probability that it will be huge​ success

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timama [110]

Answer:

Where Is the picture?

Step-by-step explanation:

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2 years ago
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