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grigory [225]
3 years ago
15

What are the steps for using a compass and straightedge to construct a square? Drag and drop the steps in order from start to fi

nish.
1.Construct a line perpendicular to line m through point F. Label a point on this line as point G.
2.Use a straightedge to draw line m and label a point on the line as point F.
3.Without changing the compass width, place the compass point on point H and draw an arc in the interior of ∠HFK .
4.Use the straightedge to draw JH¯¯¯¯¯ and JK¯¯¯¯¯.
5.With the compass open to the desired side length of the square, place the compass point on point F and draw an arc on line m and an arc on FG←→ . Label the points of intersection as points H and K.
6.Keeping the same compass width, place the compass on point K and draw an arc in the interior of ∠HFK to intersect the previously drawn arc. Label the point of intersection as point J.

Mathematics
2 answers:
Mazyrski [523]3 years ago
5 0

For those of you who are doin the test rn here are the answers to all of them. Hope this helps! ;) I did the quiz

Aleks04 [339]3 years ago
3 0
<span>The steps for using a compass and straightedge to construct a square are given as follows:

1. </span><span>Use a straightedge to draw line m and label a point on the line as point F

2. </span><span>Construct a line perpendicular to line m through point F. Label a point on this line as point G.

3. </span><span>With the compass open to the desired side length of the square, place the compass point on point F and draw an arc on line m and an arc on FG←→ . Label the points of intersection as points H and K.

4. </span><span>Without changing the compass width, place the compass point on point H and draw an arc in the interior of ∠HFK.

5. </span><span>Keeping the same compass width, place the compass on point K and draw an arc in the interior of ∠HFK to intersect the previously drawn arc. Label the point of intersection as point J.

6. </span><span>Use the straightedge to draw JH¯¯¯¯¯ and JK¯¯¯¯¯.
</span>
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Step-by-step explanation:

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Answer:

  1. y = 0.937976x +12.765
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Step-by-step explanation:

1. For this sort of question a graphing calculator or spreadsheet are suitable tools. The attached shows the linear regression line to have the equation ...

... y = 0.937976x + 12.765

where x is years since 2000, and y is average tuition cost in thousands.

2. The y-intercept is the year-2000 tuition: $12,765.

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