Question

Elizabeth brought a box of donuts to share. there are​ two-dozen (24) donuts in the​ box, all identical in​ size, shape, and color. threethree are​ jelly-filled, 44 are​ lemon-filled, and 1717 are​ custard-filled. you randomly select one​ donut, eat​ it, and select another donut. find the probability of selecting two custardcustard​-filled donuts in a row.

Answer 1

( I'm assuming it's supposed to say 3 jelly-filled, 4 lemon-filled, and 17 custard-filled since there are only 24 donuts)

this means that 3 out of 24 are jelly (3/24)
4 out of 24 are lemon (4/24)
and 17 out of 24 are custard (17/24)
the probability of eating a custard donut is then 17/24
now there are 23 donuts left, and 16 are custard. the probability of eating a custard donut is now 16/23. however, the probability of both of these happening is found by multiplying these 2 separate probabilities:

17/24 × 16/23 = 272/552
this probability is then simplified:
(272÷8)/(552÷8)= 34/69
so, the answer is 34/69, which is about a 49.3% chance