All categories

3 years ago

Paulo has $145 in his savings account. He earns $36 a week in mowing laws. Write an equation.

Mathematics

2 answers:

bazaltina [42]3 years ago

6 0

36w+145 is the equation

frozen [14]3 years ago

5 0

36w + 145
^ lawns mowed a WEEK
and then 145$ for how much in his saving accont

You might be interested in

Jenny bought a desk on sale for 119.60 the price was 75% less than the original price was the original price

olasank [31]

Answer:

100 - 75 = 25%

25%=119.60

need to find 1%

25/25=1%

119.60/25=1%

1%=4.784

now multiply by 100 to find original price

100% = 478.40

original price £478.40

5 0

3 years ago

A business was valued at £80000 at the start of 2013. In 5 years the value of this business raised to £95000. this is equivalent

dedylja [7]

Answer:

20%

Step-by-step explanation:

Value increased in 5 years = £95000 - £80000 = £5000

Value increase in 1 year =5000/5 = 1000

Increase % = (1000/5000 ) * 100 = (1/5) *100 = 20%

6 0

3 years ago

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

3 years ago

What's five divided by two

bogdanovich [222]

The answer to this problem would be 2.5.

4 0

3 years ago

Read 2 more answers

Using powers of 10, which would be the best choice for the first number to subtract in the division problem 956 ÷ 87?

dlinn [17]

Answer:

870 as it is the only number in the list which closest and lesser then 956.

(if you divide, then you get 10 as quotient and 86 as remainder)

we can also take 87 but the question mentions with multiples of 10.

Step-by-step explanation:

6 0

2 years ago