In a rhombus, all sides are equal.
So for the quadrilateral MNOP to be a rhombus, the given sides have to be equal. THat is
![MN=ON](https://tex.z-dn.net/?f=%20MN%3DON%20)
![4x-7 =7-3x](https://tex.z-dn.net/?f=%204x-7%20%3D7-3x%20%20)
Adding 3x to both sides and addinf 7 to both sides
![7x = 14](https://tex.z-dn.net/?f=%207x%20%3D%2014%20)
Now we need to get rid of 7 and for that we do division, that is
![\frac{7x}{7} = \frac{14}{7}](https://tex.z-dn.net/?f=%20%5Cfrac%7B7x%7D%7B7%7D%20%3D%20%5Cfrac%7B14%7D%7B7%7D%20)
![x=2](https://tex.z-dn.net/?f=%20x%3D2%20)
Correct option is the second option .
You can use the similarity approach of these two triangles CBD and CAE
as a result:
![\frac{BD}{AE} = \frac{10}{2x} = \frac{CD}{CE} = \frac{3x}{?}](https://tex.z-dn.net/?f=%20%5Cfrac%7BBD%7D%7BAE%7D%20%3D%20%5Cfrac%7B10%7D%7B2x%7D%20%3D%20%5Cfrac%7BCD%7D%7BCE%7D%20%3D%20%5Cfrac%7B3x%7D%7B%3F%7D%20)
so:
? = 6x^2 / 10 = 0.6 x^2
and the fact of:
"The
segment connecting the midpoints of two sides of a triangle is parallel to the
third side and equals its half length"
so:BD = 0.5 AE 10 = 0.5 * 2x >>> x= 10
Back to:
? =0.6 x^2 = 0.6 * 10^2 = 0.6 * 100 = 60
AHope that helps
Answer:
bnmn
Step-by-step explanation:
jm
What is this about because I’m confuse
Answer:
Height of tree is
<em>15 m.</em>
<em></em>
Step-by-step explanation:
Given that student is 20 m away from the foot of tree.
and table is 1.5 m above the ground.
The angle of elevation is: 34°28'
Please refer to the attached image. The given situation can be mapped to a right angled triangle as shown in the image.
AB = CP = 20 m
CA = PB = 1.5 m
= 34°28' = 34.46°
To find TB = ?
we can use trigonometric function tangent to find TP in right angled ![\triangle TPC](https://tex.z-dn.net/?f=%5Ctriangle%20TPC)
![tan \theta = \dfrac{Perpendicular}{Base}\\tan C= \dfrac{PT}{PC}\\\Rightarrow tan 34.46^\circ = \dfrac{PT}{20}\\\Rightarrow PT = 20 \times 0.686 \\\Rightarrow PT = 13.72\ m](https://tex.z-dn.net/?f=tan%20%5Ctheta%20%3D%20%5Cdfrac%7BPerpendicular%7D%7BBase%7D%5C%5Ctan%20C%3D%20%5Cdfrac%7BPT%7D%7BPC%7D%5C%5C%5CRightarrow%20tan%2034.46%5E%5Ccirc%20%3D%20%5Cdfrac%7BPT%7D%7B20%7D%5C%5C%5CRightarrow%20PT%20%3D%2020%20%5Ctimes%200.686%20%5C%5C%5CRightarrow%20PT%20%3D%2013.72%5C%20m)
Now, adding PB to TP will give us the height of tree, TB
Now, height of tree TB = TP + PB
TB = 13.72 + 1.5 = 15.22
<em>15 m</em>