1. Function
2. Not Function
Answer:
The original price of the tent = $320
Step-by-step explanation:
Let the original price be =$ 
Discount offered = 
% of the orignal price = 
Original price is $80 more than sale price
Discount = Original price - Sale price = $80
So, we have
We need to solve for to find original price
Dividing both sides by 
∴ The original price of the tent = $320
Answer:
6720 ft³
Step-by-step explanation:
Volume = 
* base * height * length
Here the base is 14 ft, height is 24 ft and length is 40 ft
using the formula:
* 14* 24* 40
6720 ft³
(1) <span>The surface area of the square pyramid = 4 * (area of one face) + area of the base
area of one face = 0.5 * 34.2 * 28.4
area of the base = 34.2 * 34.2
∴ </span>The surface area of the pyramid = 4 * (<span>0.5 * 34.2 * 28.4) + </span><span>34.2 * 34.2
By comparing the last answer with the answer of </span>Vikram, we find that:
He used the wrong expression to represent the area of the base of the pyramid.
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(2) The surface area of the rectangular pyramid
= area of two face with the height 36.5 + area of two face with the height 37.8 + area of the base
area of two face with the height 36.5 = 2 * 0.5 * 36.5 * 25.6
area of two face with the height 37.8 = 2 * 0.5 * 37.8 * 16.2
are of the base = 25.6 * 16.2
Total area = (2 * 0.5 * 36.5 * 25.6) + (2 * 0.5 * 37.8 * 16.2) + (25.6 * 16.2)
= (36.5 * 25.6) + (37.8 * 16.2) + (25.6 * 16.2)
note: 2 *0.5 = 1
By comparing the last answer with the answer of Tracy , we find that:
<span>Tracy’s answer will be correct because she made use of the fact that 2 (1/2) = 1 in her expression.
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</span>
(3)
the total surface area of this rectangular pyramid =
= area of two face with the height 52 + area of two face with the height 60 + area of the base
area of two face with the height 52 = 2 * 0.5 * 52 * 78 = 4,056 m²
area of two face with the height 60 = 2 * 0.5 * 60 * 50 = 3,000 m²
are of the base = 78 * 50 = 3900 m²
Total area = 4,056 + 3,000 + 3,900 = 10,956 m²
Answer:
<h3>X<5 and X<3</h3>
Step-by-step explanation:
To solve this problem, first, you have to isolate it on one side of the equation. Remember to solve this problem, isolate x on one side of the equation.
x+3<8 and 3(x+4)-11<10
x+3<8
x+3-3<8-3 (First, subtract 3 from both sides.)
8-3 (Solve.)
8-3=5
x<5
3(x+4)-11<10
3(x+4)-11+11<10+11 (Add 11 from both sides.)
10+11 (Solve.)
10+11=21
3(x+4)<21
3(x+4)/3<21/3 (Next, divide by 3 from both sides.)
21/3 (Solve.)
21/3=7
x+4<7
x+4-4<7-4 (Then, subtract 4 from both sides.)
7-4=3
x<3
The correct answer is x<5 and x<3.
