Help me please ????????????????????

stans cookie recipe makes 24 cookies and calls for exactly 384 sprinkles. he is wondering how many sprinkles (p) he will need to

Angelina_Jolie [31]

Answer:

960 sprinkles

Step-by-step explanation:

If 24 cookies call for EXACTLY 384 sprinkles, then 16 sprinkles fit on each cookie. 384/24 = 16

If 16 sprinkles fit on each cookie, 16 cookies on 60 cookies would be 960.

60 x 16 = 960

4 0

2 years ago

A rectangular swimming pool has an area of (70x+10) square feet. Find possible dimensions of the pool.

NNADVOKAT [17]

Answer:

10 and 7x + 1

Step-by-step explanation:

The area of a rectangle is 70x + 10.

Let's factor 70x + 10.

Factor out a common factor of 10.

70x + 10 = 10(7x + 1)

Since the area of a rectangle is length * width, we can let one factor be the length and the other factor be the width.

Possible dimensions are 10 and 7x + 1

6 0

2 years ago

Read 2 more answers

How do you find 55% of 140?

yaroslaw [1]

If you type in calculator on google click the buttons and do 140 divided by 55% but the long way to do a percentage problem is to find 1% of the number you start off with and multiply it by the percentage so in this case 1% of 140 would be 1.4 and multiply that by 55 t

3 0

2 years ago

Which portion of the unit circle satisfies the trigonometric inequality cos^2theta + sin^2theta is greater than or equal to 1. A

liberstina [14]

Answer:

Only points on the circle satisfy the given inequality.

Step-by-step explanation:

Given: Unit circle

To find: portion of the unit circle which satisfies the trigonometric inequality $\sin ^2\theta +\cos ^2\theta \geq 1$

Solution:

In the given figure, OA = 1 unit (as radius of the unit circle equal to 1)

$\sin \theta$ = side opposite to $\theta$ /hypotenuse

$\cos \theta$ = side adjacent to $\theta$ /hypotenuse

$\sin \theta =\frac{AB}{AO}\\\sin \theta =\frac{AB}{1}\\AB=\sin \theta$

$\cos \theta=\frac{OB}{AO}\\\cos \theta =\frac{OB}{1}\\OB=\cos \theta$

So, coordinates of A = $\left ( \cos \theta ,\sin \theta \right )$

For any point (x,y) on the unit circle with centre at origin, equation of circle is given by $x^2+y^2=1$

Put $(x,y)=\left ( \cos \theta ,\sin \theta \right )$

$\cos ^2\theta +\sin ^2\theta =1$

So, $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ satisfies the equation $x^2+y^2=1$

For points $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ inside the circle, $\cos ^2\theta +\sin ^2\theta$

For points $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ outside the circle, $\cos ^2\theta +\sin ^2\theta >1$

So, only points on the circle satisfy the given inequality.

4 0

2 years ago

Read 2 more answers

Please help, easy geometry

iVinArrow [24]

Answer:

26 cm²

Step-by-step explanation:

The area of the rectangle whose dimensions are shown at the right and bottom is ...

(6 cm)(7 cm) = 42 cm²

The figure is smaller than that by the area of the space whose dimensions are shown at the right and in the middle left:

(4 cm)(4 cm) = 16 cm²

The figure area is then the difference ...

42 cm² - 16 cm² = 26 cm²

_____

<em>Alternate solution</em>

Draw a diagonal line between the lower right inside corner and the lower right outside corner. This divides the figure into two trapezoids.

The trapezoid at lower left has bases 7 and 4 cm, and height 6-4 = 2 cm. Its area is ...

A = (1/2)(b1 +b2)h = (1/2)(7 + 4)(2) = 11 . . . . cm²

The trapezoid at upper right has bases 6 cm and 4 cm and height 3 cm. Its area is ...

A = (1/2)(b1 +b2)h = (1/2)(6 + 4)(3) = 15 . . . . cm²

Then the area of the figure is the sum of the areas of these trapezoids, so is ...

11 cm² + 15 cm² = 26 cm²

_____

<em>Comment on other alternate solutions</em>

There are many other ways you can find the area of this figure. It can be divided into rectangles, triangles, or other figures of your choice. The appropriate area formulas should be used, and the resulting partial areas added or subtracted as required.

You can also let a geometry program find the area for you. (It is 26 cm².)

8 0

3 years ago