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3 years ago

5

Peter opens a new bookstore and pays the book publisher $3.00 for each book he buys from them. The amount Peter pays is given by

F (x) = 3x, where x is the number of books purchased.

1 answer:

melisa1 [442]3 years ago

7 0

F(x) = 3x ; where x is the number of books purchased.

x f(x)
0 0
1 3
2 6
3 9
4 12
5 15

I saw this problem and the instruction was to graph the function and show the domain and range.

The domain is all the x-values while the range is all the y-values.

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HOW DO I SOLVE THIS PLEASE HELP

LenKa [72]

Answer:

64

Step-by-step explanation:

Euclide's theorem states that in a right triangle, the square built of the side lenght is equivalent of the rectangle with sides hypotenuse and projection of the same side lenght. In formula, given the measures on the triangle:

$60^2 = (36+x)(36) \rightarrow 3600 = 36(x+36) \rightarrow 100=x+36\\ x=64$

3 0

2 years ago

For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

5 0

3 years ago

Which figure appears to show a line with a slope of 1?

gulaghasi [49]

Answer:

I believe it is figure 1

7 0

3 years ago

Read 2 more answers

5x7/8 less than or greater

Pavel [41]

5x7= 35
35> (greater than) 8

5 0

3 years ago

Read 2 more answers

Which statements are true?<br>(look at picture)

Makovka662 [10]

Answer:

D is true, E is true, F is true

Step-by-step explanation:

Hello,

n is an odd number it means that n = 2a+1 where a is integer

A

$n^2-1=(2a+1)^2-1=4a^2+4a+1-1=4a(a+1)$

this is <u>not</u> an odd number

B

$n(n-1)=(2a+1)2a$

this is <u>not</u> an odd number

C

$(n-1)^2=(2a+1-1)^2=4a^2$

this is <u>not</u> an odd number

D

$n^2+2=(2a+1)^2+2=4a^2+4a+1+2=4a^2+4a+3= 2(2a^2+2a+1)+1$

so this is an odd number

E

$n(n-2)=(2a+1)(2a-1)=4a^2-1=4a^2-2+1=2(2a^2-1)+1$

so this is an odd number

F

$(n-2)^2=(2a+1-2)^2=(2a-1)^2=4a^2-4a+1 = 2(2a^2-2a)+1$

this is an odd number

hope this helps

7 0

3 years ago