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dimaraw [331]
3 years ago
12

Koalas sleep about 22 hours a day. pandas sleep about 10 hours a day. About how many more hours does a typical kola sleep in 1 y

ear than a panda what is the estimate
Mathematics
1 answer:
12345 [234]3 years ago
5 0
Koala -22×365(days in a year)=8,030 hours in a year

panda-10×365(days in a year)=3,650

8,030-3,650=4,380

koalas sleep 4380 hours more than a panda

there's your answer :)
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The graph of a system of equations with the same slope and the same y-intercepts will have no solutions.
Liula [17]
I think the correct answer from the choices listed above is option C. <span>The graph of a system of equations with the same slope and the same y-intercepts will never have no solutions. Rather, it has an infinite number of solutions since all points of the lines intersects.</span>
4 0
3 years ago
Rick is on a bicycle trip. Every 444 days he bikes 230 \text{ km}230 km230, space, k, m.If Rick keeps this same pace for 161616
Katarina [22]
For this problem, we use the approach of ratio and proportion. Assuming that the given ratio of 444 days per 230 km is constant all throughout, we can determine the number of days or distance as long as one of the two is given. In this case, the solution is as follows:

444 days/230 km = 161616 days/distance
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4 0
3 years ago
Brian has 14 bins and 70 books. He places the same number of books, x in each bin.
adelina 88 [10]

Answer:

14x=70

Step-by-step explanation:

5 0
3 years ago
Implicit differentiation of 1/x +1/y=5 y(4)= 4/19<br> y'(4)=?
Aneli [31]
\frac{1}{x} +\frac{1}{y} = 5\\\\x^{-1}+y^{-1}=5\\

Above, I changed the fraction form of x and y into exponential form so it is easier to see the differentiation. Now, we can differentiate:

-1x^{-2}+-1y^{-2}\frac{dy}{dx}=5\\\\\frac{-1}{x^2}-\frac{1}{y^2}\frac{dy}{dx}=5\\\\-\frac{1}{y^2}\frac{dy}{dx}=5+\frac{1}{x^2}\\\\\frac{dy}{dx}=-5y^2-\frac{y^2}{x^2}

Now that we have dy/dx, we can plug in the x, which is 4, and the y, which is 4/19. We know these values of x and y because your question stated y(4) = 4/19.

\frac{dy}{dx}=-5(\frac{4}{19})^2-\frac{(\frac{4}{19})^2}{(4)^2}\\\\\frac{dy}{dx}=-5(\frac{16}{361})-\frac{(\frac{16}{361})}{16}\\\\\frac{dy}{dx}=\frac{-80}{361}-\frac{1}{361}\\\\\frac{dy}{dx}=\frac{-81}{361}
5 0
4 years ago
bag contains 15 marbles numbered from 1 to 15. Two marbles are selected from the bag at the same time. Let event E = the two num
lbvjy [14]
The numbers DO differ by 10 if they are

- 1 and 11
- 2 and 12
- 3 and 13
- 4 and 14
- 5 and 15

Each outcome technically has two ways of occurring, but since we're taking two marbles at a time, that would be the same as saying, for instance, that drawing 1 and 11 is the same as drawing 11 and 1. We only count such an event once.

So the answer is (a) 5.
7 0
3 years ago
Read 2 more answers
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