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3 years ago

11

Maria has an 8 sided die that is numbered from 1 to 8 she rolls the die 96 times about how many times can she expect to roll an

8

2 answers:

Lelechka [254]3 years ago

6 0

12 times, 96/8 = 12. :)+

alukav5142 [94]3 years ago

4 0

Answer:

12

Step-by-step explanation:

you have to 1/8 and put 96 as your numerate and then divided 96 from 8 and you get 12

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18.75 divided by 0.70

Mkey [24]

Answer:

26.79 (rounded to the nearest hundredth)

6 0

3 years ago

If x and y are both negative when is x-y positive

jarptica [38.1K]

Hmm

let's try some numbers

we have 3 scenarios
x>y
x=y
x<y

x>y
x=-1 and y=-2
x-y=-1-(-2)=-1+2=1
it's positive when x>y

x=y
x=-1, y=-1
-1-(-1)=-1+1=0
nope

x<y
x=-2 and y=-1
-2-(-1)=-2+1=-1
nope

x-y is positive when 0>x>y

4 0

3 years ago

Read 2 more answers

What is the length in cm of s i need help

Romashka [77]

Answer:

12.8

Step-by-step explanation:

A squared plus B squared equals C squared

6 0

2 years ago

Read 2 more answers

Match the system of equations on the left with the number of solutions on the right

erastova [34]

Answer:

top to bottom, the answers are b, c, a

Step-by-step explanation:

One way to find the solution to a system of equations is to substitute values in. For the first one,

y=2x+3

y=2x+5,

we can substitute 2x+3 =y into the second equation to get

y=2x+5

2x+3 = 2x+5

subtract 2x from both sides

3 = 5

As 3 is not equal to 5, this is never equal and therefore has no solution

For the second one,

y= 2x+7

y = (-2/3)x + 10

We can plug y=2x+7 into the second equation to get

2x + 7 = y = (-2/3)x + 10

2x + 7 = (-2/3)x + 10

add (2/3)x to both sides to make all x values on one side

2x + (2/3)x + 7 = 10

subtract 7 from both sides to make only x values on one side and only constants on the other

2x + (2/3)x = 3

(6/3)x + (2/3)x = 3

(8/3)x = 3

multiply both sides by 3 to remove a denominator

8x = 9

divide both sides by 8 to isolate x

x=9/8

There is only one value for when the equations are equal, so this has one solution

For the third one

y = x-5

2y = 2x - 10

Plug x-5 = y into the second equation

2 * y= 2*(x-5)

2 * (x-5) = 2x - 10

2x-10 = 2x-10

add 10 to both sides

2x=2x

As 2x is always equal to 2x, no matter what x is, there are infinitely many solutions for this system

6 0

3 years ago

Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best po

mina [271]

Answer:

(a) The point estimate for the population proportion <em>p</em> is 0.34.

(b) The margin of error for the 99% confidence interval of population proportion <em>p</em> is 0.055.

(c) The 99% confidence interval of population proportion <em>p</em> is (0.285, 0.395).

Step-by-step explanation:

A point estimate of a parameter (population) is a distinct value used for the estimation the parameter (population). For instance, the sample mean $\bar x$ is a point estimate of the population mean <em>μ</em>.

Similarly, the the point estimate of the population proportion of a characteristic, <em>p</em> is the sample proportion $\hat p$ .

The (1 - <em>α</em>)% confidence interval for the population proportion <em>p</em> is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The margin of error for this interval is:

$MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The information provided is:

$\hat p=0.34\\n=500\\(1-\alpha)\%=99\%$

(a)

Compute the point estimate for the population proportion <em>p</em> as follows:

Point estimate of <em>p</em> = $\hat p$ = 0.34

Thus, the point estimate for the population proportion <em>p</em> is 0.34.

(b)

The critical value of <em>z</em> for 99% confidence level is:

$z={\alpha/2}=z_{0.01/2}=z_{0.005}=2.58$

*Use a <em>z</em>-table for the value.

Compute the margin of error for the 99% confidence interval of population proportion <em>p</em> as follows:

$MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=2.58\sqrt{\frac{0.34(1-0.34)}{500}}$

$=2.58\times 0.0212\\=0.055$

Thus, the margin of error for the 99% confidence interval of population proportion <em>p</em> is 0.055.

(c)

Compute the 99% confidence interval of population proportion <em>p</em> as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$CI=\hat p\pm MOE$

$=0.34\pm 0.055\\=(0.285, 0.395)$

Thus, the 99% confidence interval of population proportion <em>p</em> is (0.285, 0.395).

6 0

3 years ago