Answer:
The width is 50 yards and the length is 141 yards.
Step-by-step explanation:
Let's call: L the length of the field and W the width of the field.
From the sentence, the perimeter of the rectangular playing field is 382 yards we can formulate the following equation:
2L + 2W = 382
Because the perimeter of a rectangle is the sum of two times the length with two times the width.
Then, from the sentence, the length of the field is 9 yards less than triple the width, we can formulate the following equation:
L = 3W - 9
So, replacing this last equation on the first one and solving for W, we get:
2L + 2W = 382
2(3W - 9) + 2W = 382
6W -18 +2W = 382
8W - 18 = 382
8W = 382 + 18
8W = 400
W = 400/8
W = 50
Replacing W by 50 on the following equation, we get:
L = 3W - 9
L = 3(50) - 9
L = 141
So, the width of the rectangular field is 50 yards and the length is 141 yards.
Answer:
- 20 + 8i
Step-by-step explanation:
Noting that i² = - 1
Given
[(6i + 9) + (4i - 5)] × 2i ← evaluate the terms inside the square bracket
= ( 6i + 9 + 4i - 5 ) × 2i
= (10i + 4) × 2i ← multiply each term in the parenthesis by 2i
= 20i² + 8i
= 20(- 1) + 8i
= - 20 + 8i
It’s a great way to write numbers that are very big numbers or very small numbers.
Have a great day!
Answer:
1). a = 9.42 m
2). b = 6.37 m
3). c = 4.48 m
Step-by-step explanation:
In the figure attached,
By applying tangent rule in triangle ADE,
tan47 = 
c = 
c = 
c = 4.476
c ≈ 4.48 m
Now we apply the same rule in triangle ACE,
tan37° = 
b = 
b = 
b = 6.37 m
Now apply the tangent in triangle ABE,
tan27° = 
a = 
a = 
a = 9.42 m
