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3 years ago

Determine the equation of the line with slope 3 that passes through the point (2, 0).

Mathematics

2 answers:

Hitman42 [59]3 years ago

8 0

Answer:

m=2y-3

Step-by-step explanation:

Dahasolnce [82]3 years ago

5 0

Answer:

y=3x-6

Step-by-step explanation:

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I need help ASAP please

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3 years ago

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Solve for the given variable 7x+5y=6 for y

olga_2 [115]

Answer:

y = (6/5) - (7/5) x

Step-by-step explanation:

goal: to rearrange the equation such that it takes the form:

y = f(x) ; where f(x) is an expression in terms of x

Given:

7x+5y=6 subtract 7x from both sides

5y = 6 - 7x (divide both sides by 5)

y = (6-7x) / 5

y = (6/5) - (7/5) x

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3 years ago

Evaluate the expression 4b-6d if b=7 and d=3

Delicious77 [7]

Answer:

Step-by-step explanation:

4b - 6d = 4*7 - 6*3

= 28 - 18

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4 years ago

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Jack borrows 2000 for 2 years at a rate of 2% how much interest will he owe

neonofarm [45]

2000 x 2 x 0.02 = 80
answer
interest will be $80

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3 years ago

Given right triangle ABCABC with altitude \overline{BD} BD drawn to hypotenuse ACAC. If BC=10BC=10 and DC=5,DC=5, what is the le

Helen [10]

Answer: $\overline{AC}=$ 12.5

Step-by-step explanation: The triangle ABC and its altitude $\overline{BD}$ is represented in the figure below.

<u>Altitude</u> is a segment of line that link a vertex and the opposite side, forming a right angle.

So, because of $\overline{BD}$ , now we have two similar triangles, which means that ratios of corresponding sides are equal:

$\frac{\overline{BD}}{\overline{BC}} =\frac{\overline{AD}}{\overline{BD}}$

$\overline{BD}^{2}=\overline{BC}.\overline{AD}$ (1)

This is always true for a right triangle and a altitude drawn to the hypotenuse.

Triangle BDC is also right triangle. So, we can use Pythagorean theorem to determine the missing side.

$\overline{BC}^{2}=\overline{CD}^{2}+\overline{BD}^{2}$

$\overline{BD}^{2}=\overline{BC}^{2}-\overline{CD}^{2}$ (2)

Substituting (2) into (1):

$\overline{BC}^{2}-\overline{CD}^{2}=\overline{BC}.\overline{AD}$

We want to find f, so:

$\overline{AD}=\frac{\overline{BC}^{2}-\overline{CD}^{2}}{\overline{BC}}$

$f=\frac{10^{2}-5^{2}}{10}$

f = 7.5

The length of $\overline{AC}$ is

$\overline{AC}=f+5$

$\overline{AC}=7.5+5$

$\overline{AC}=12.5$

The length of the hypotenuse of triangle ABC is 12.5 units.

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3 years ago

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