Determine the equation of the line with slope 3 that passes through the point (2, 0).

Mathematics

2 answers:

Hitman42 [59]2 years ago

8 0

Answer:

m=2y-3

Step-by-step explanation:

Dahasolnce [82]2 years ago

5 0

Answer:

y=3x-6

Step-by-step explanation:

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The sum of the squares of two consecutive negative integers is 61. Find the smaller of the two integers

Marysya12 [62]

$x^2+(x+1)^2=61\\ x^2+x^2+2x+1-61=0\\ 2x^2+2x-60=0\ \ /:2\\ x^2+x-30=0\\ \Delta=1^2-4\cdot(-40)=1+120=121\ \ \Rightarrow\ \ \sqrt{\Delta} =11\\ \\ x_1= \frac{-1-11}{2} = \frac{-12}{2} =-6,\ \ \ \ x_2= \frac{-1+11}{2} = \frac{10}{2}=5\\ \\Ans.:x=-6$

3 0

3 years ago

I WILL GIVE YOU BRAINLIEST, AND 30 POINTS SO PLEASE HELP ME, IT'S URGENT!

IRINA_888 [86]

Answer:

Answer is option b)

${(x - 3)}^{2} + {(y - 4)}^{2} = 400$

Your guess was right.

Step-by-step explanation:

$the \: question \: states \: that \: \\ distance \: between \: two \: points \: is \: 20 \: units \: \\ and \: the \: two \: points \: are \: (x,y) \: \: and \: \: (3 ,- 4) \\ distance \: formula \\ = \sqrt{ {(x1 - x2) }^{2} + {(y1 - y2)}^{2} } \\ on \: substituting \: the \: values \: in \: formula \\ 20 = \sqrt{ {(x - 3)}^{2} + {(y - ( - 4))}^{2} } \\ 20 = \sqrt{ {(x - 3)}^{2} + {(y + 4)}^{2} } \\ now \: squaring \: on \: both \: sides \\ 400 = {(x - 3)}^{2} + {(y + 4)}^{2} \\ hence \: the \: answer \: is \: option \: b)$