Answer:
See Explanation
Step-by-step explanation:
Given
--- Number of tryouts
Required
Determine the average distance
<em>This question has missing details, as the distance he hits the ball in each tryout is not given. However, I'll give a general explanation.</em>
<em></em>
The mean is calculated as:
![\bar x = \frac{\sum x}{n}](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%20%5Cfrac%7B%5Csum%20x%7D%7Bn%7D)
means the sum of the distance in each tryout.
Assume that the distance in the 10 tryouts are: ![6, 8, 5, 9, 4, 5, 8, 7, 7, 6.](https://tex.z-dn.net/?f=6%2C%208%2C%205%2C%209%2C%204%2C%205%2C%208%2C%207%2C%207%2C%206.)
So, the mean is:
![\bar x = \frac{6+ 8+ 5+ 9+ 4+ 5+ 8+ 7+ 7+ 6}{10}](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%20%5Cfrac%7B6%2B%208%2B%205%2B%209%2B%204%2B%205%2B%208%2B%207%2B%207%2B%206%7D%7B10%7D)
![\bar x = \frac{65}{10}](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%20%5Cfrac%7B65%7D%7B10%7D)
![\bar x = 6.5}](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%206.5%7D)
<em>So, the average distance is 6.5</em>
(-1,1.5) because you add both ys and both xs then divide by two to find the middle
A. 485 is %3 of 500, but the deviation sets it slightly lower than that
Answer:
substitute x=1/2 in the equation then it will be
![8 + 2( \frac{ 1}{2} ) \\ = 9](https://tex.z-dn.net/?f=8%20%2B%202%28%20%5Cfrac%7B%201%7D%7B2%7D%20%29%20%5C%5C%20%20%3D%209)
PQS = 40 because if you look at the image above it half equals 20 and 20+20=40