Yes I can What is your queastion
9514 1404 393
Answer:
(a) 31.5 in²
Step-by-step explanation:
The area of a rhombus is half the product of the lengths of the diagonals.
A = 1/2(d1)(d2)
A = (1/2)(7 in)(9 in) = 31.5 in²
There are 31.5 in² of space in the rhombus for engraving.
The age of Blain is 23 years old
<h3><u>Solution:</u></h3>
Let the age of Blain be "a" and age of Jillian be "b"
Given that Blain is two years older than three times Jillians age
So we can frame a equation as:
age of blain = 2 + 3(age of Jillian)
a = 2 + 3b ----- eqn 1
Also given that Jillian is also 16 years younger than Blain
Age of Jillain = Age of Blain - 16
b = a - 16 ---- eqn 2
Substitute eqn 2 in eqn 1
a = 2 + 3(a - 16)
a = 2 + 3a - 48
a - 3a = -46
-2a = -46
a = 23
Thus the age of Blain is 23 years old
Fraction -> Decimal
4/5 = 0.8
1/8 = 0.125
Decimal -> Percent
0.22 * 100% = 22%
0.47 * 100% = 47%
Percent -> Fraction
34% / 100 = 0.34 = 17/50
25% / 100 = 0.25 = 1/4
Fraction -> Percent
1/3 = 0.33... * 100% = 33.3%
2/5 = 0.4 * 100% = 40%
Decimal -> Fraction
0.65 = 65/100 = 13/20
0.4 = 4/10 = 2/5
Percent -> Decimal
81% / 100 = 0.81
4% / 100 = 0.04
Best of Luck!