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enyata [817]
4 years ago
6

Express 0.000089 in scientific notation

Mathematics
1 answer:
MrRissso [65]4 years ago
5 0
8.9 x 10^-5 in scientific notation
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A t-shirt decreased in price by
snow_tiger [21]

Answer:

£20

Step-by-step explanation:

1-1/4=3/4

3/4=15

1

1*15/3/4

15*4/3=20

7 0
3 years ago
At a zoo, youth tickets cost $5 and adult tickets cost $9. A group that purchased x youth tickets and y adult tickets spent $90
Marrrta [24]

Answer:

0 ≤ x ≤ 18

Step-by-step explanation:

Let 'x' be the number of youth tickets purchased at the zoo and 'y' be the number of adult tickets purchased at the zoo.

At a zoo, youth tickets cost $5 and adult tickets cost $9. A group spent a total of $90 on tickets. We can write as

5x + 9y = 90

to find x we divide both side by 5

x = (90-9y)/5 =>  90/5 - 9y/5

x = 18 - 9y/5

The domain of the relationship is the possible set of values of x and y that satisfies the equation. The domain of this relationship is

0 ≤ x ≤ 18

At x = 0, it means only adult tickets were purchased.

At x = 18, it means only youth tickets were purchased.

4 0
3 years ago
Need help! What is the length of one side of the square?
scoray [572]

Answer:4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Giovanni had seven rows of trading cards each row had five cards then he added three new cards how many cars are there altogethe
natali 33 [55]
Your answer is 38 because 7x5+3 is 38.
4 0
3 years ago
Some students were asked what kinds of animals they have at home.
Nataly_w [17]

(a) Animals by popularity; Dogs, Cats, Others, Horses.

(b) If 250 students were interviewed, 20 students have other pets.

(c) No, it was incorrect.

Step-by-step explanation:

Step 1; We arrange the different pets in chronological order, from the highest percent to the lowest percent;

1. Dogs - 67%,

2. Cats - 20%

3. Others - 8%,

4. Horses - 1%.

None is not included in this list.

Step 2; If 250 students were interviewed, 8% of those have other pets. So we need to calculate how much 8% of 250 is.

8% of 250 = \frac{8}{100} × 250 = 0.08 × 250 = 20.

So 20 students had other pets.

Step 3; 20% of the interviewed students had cats. If 75 students had cats, we need to equate 20% to the 75 and find out how many students were actually interviewed.

20% × x = 75, 0.2 × x = 75,

x = \frac{75}{0.2} = 375.

So if 375 students were interviewed, 75 students would have cats. So the estimate of 250 students being interviewed is incorrect.

8 0
3 years ago
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